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masya89 [10]
3 years ago
12

Anyone know the answer ?

Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

a,c,d I thought these are the true statements about these graph

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Explain how if two cases are side by side on a shelf one an have more potential energy
Arlecino [84]

Potential energy = (mass) x (gravity) x (height).

Even if the two objects are at the same height, the one
with more mass has more potential energy.

6 0
3 years ago
There is more role of the moon than the sun to occur tides in oceans?why?
Leya [2.2K]
The ocean tides on earth are caused by both the moon's gravity and the sun's gravity. ... Even though the sun is much more massive and therefore has stronger overall gravity than the moon, the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.
6 0
3 years ago
A car that experiences no frictional force is started and caused to move. For the car to continue in that motion, the gas pedal
astraxan [27]

Explanation:

Gas pedal is not required to used on friction less surface. On a friction less surface once the car is started and caused to move, car continues to move with same velocity as there is no opposing force. Therefore, no pressing of gas pedal required. However, this situation is not possible in real life, as friction is always present.

8 0
3 years ago
When an object is placed 110 cm from a diverging thin lens, its image is found to be 55 cm from the lens. The lens is removed, a
Kazeer [188]

Explanation:

Given that,

Object distance u= -110 cm

Image distance v= 55 cm

We need to calculate the focal length for diverging lens

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{-f}=\dfrac{1}{55}-\dfrac{1}{-110}

\dfrac{1}{f}=-\dfrac{3}{110}

f=-36.6\ cm

The focal length of the diverging lens is 36.6 cm.

Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.    

Here, The object distance is again the same.

We need to calculate the image distance for converging lens

Using formula of lens

\dfrac{1}{36.6}=\dfrac{1}{v}-\dfrac{1}{-110}

Here, focal length is positive for converging lens

\dfrac{1}{v}=\dfrac{1}{36.6}-\dfrac{1}{110}

\dfrac{1}{v}=\dfrac{367}{20130}

v=54.85\ cm

The distance of the image is 54.85 cm from converging lens.

Hence, This is the required solution.

5 0
3 years ago
A certain force gives object m1 an acceleration of 12.0 m/s2. The same force gives object m2 an acceleration of 3.30 m/s2. What
zhenek [66]

Answer:

a)   a = 4,552 m / s²,   b)  a = 2,588 m / s²

Explanation:

Newton's second law is

          F = ma

          a = F / m

in this case the force remains constant

indicate us

* for a mass m₁

       a₁ = F/m₁

       a₁ = 12, m/ s²

* for a mass m₂

        a₂= 3.3 m / s²

a) acceleration

       m = m₂-m₁

we substitute

        a = \frac{F}{m_2 - m_1}

        1 / a = \frac{m_2}{F}  -  \frac{m_1}{F}

let's calculate

        \frac{1}{a} = \frac{1}{3.3} - \frac{1}{12}

         \frac{1}{a} = 0.21969

         a = 4,552 m / s²

b)   m = m₂ + m₁

     a = F / (m₂ + m₁)

     \frac{1}{a}  =  \frac{m_2}{F} + \frac{m_1}{F}

we substitute

           \frac{1}{a} = \frac{1}{3.3} + \frac{1}{12}

           a = 2,588 m / s²

3 0
3 years ago
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