Answer:
a) P(B'|A) = 0.042
b) P(B|A') = 0.625
Step-by-step explanation:
Given that:
80% of the light aircraft that disappear while in flight in a certain country are subsequently discovered
Of the aircraft that are discovered, 63% have an emergency locator,
whereas 89% of the aircraft not discovered do not have such a locator.
From the given information; it is suitable we define the events in order to calculate the probabilities.
So, Let :
A = Locator
B = Discovered
A' = No Locator
B' = No Discovered
So; P(B) = 0.8
P(B') = 1 - P(B)
P(B') = 1- 0.8
P(B') = 0.2
P(A|B) = 0.63
P(A'|B) = 1 - P(A|B)
P(A'|B) = 1- 0.63
P(A'|B) = 0.37
P(A'|B') = 0.89
P(A|B') = 1 - P(A'|B')
P(A|B') = 1 - 0.89
P(A|B') = 0.11
Also;
P(B ∩ A) = P(A|B) P(B)
P(B ∩ A) = 0.63 × 0.8
P(B ∩ A) = 0.504
P(B ∩ A') = P(A'|B) P(B)
P(B ∩ A') = 0.37 × 0.8
P(B ∩ A') = 0.296
P(B' ∩ A) = P(A|B') P(B')
P(B' ∩ A) = 0.11 × 0.2
P(B' ∩ A) = 0.022
P(B' ∩ A') = P(A'|B') P(B')
P(B' ∩ A') = 0.89 × 0.2
P(B' ∩ A') = 0.178
Similarly:
P(A) = P(B ∩ A ) + P(B' ∩ A)
P(A) = 0.504 + 0.022
P(A) = 0.526
P(A') = 1 - P(A)
P(A') = 1 - 0.526
P(A') = 0.474
The probability that it will not be discovered given that it has an emergency locator is,
P(B'|A) = P(B' ∩ A)/P(A)
P(B'|A) = 0.022/0.526
P(B'|A) = 0.042
(b) If it does not have an emergency locator, what is the probability that it will be discovered?
The probability that it will be discovered given that it does not have an emergency locator is:
P(B|A') = P(B ∩ A')/P(A')
P(B|A') = 0.296/0.474
P(B|A') = 0.625
Answer:
M<2= 65
Step-by-step explanation:
The reason it is 65 because 2 angles add up to either 90 or 180 and in this case it would be 180.
You would use angle addition postulate to find the answer so M<1 + M<2 = 180.
Since M<1 is 115 you would substitute it into the formula so 115 + M<2 = 180
Then you would subtract 115 from 180 in which you would get M<2 = 65
The value of the derivative of functions h'(6) as requested in the task content is; 55.
<h3>What is the value of h'(6)?</h3>
Since it follows from the task content that the function h(x)=4f(x)+5g(x)+1.
Hence, the derivative of h(x) can be evaluated as;
h'(x)=4f'(x)+5g'(x)
On this note, by substitution, it follows that;
h'(6)=4(5)+5(7)
h'(6) = 55.
Read more on functions;
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Answer: The answer is ![\textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation: The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.](https://tex.z-dn.net/?f=%5Ctextup%7BThe%20other%20root%20is%20%7D%5Cdfrac%7B8%7D%7B3%7D~%5Ctextup%7Band%7Dq%3D40.%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%20%20%3C%2Fstrong%3EThe%20given%20quadratic%20equation%20is%3C%2Fp%3E%3Cp%3E%5Btex%5D3x%5E2%2B7x-q%3D0%5C%5C%5C%5C%5CRightarrow%20x%5E2-%5Cdfrac%7B7%7D%7B3%7Dx-%5Cdfrac%7Bq%7D%7B3%7D%3D0.)
Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.
Let the other root of the equation be 'p'. So, we have

and

Thus, the other root is
and the value of 'q' is 40.