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SSSSS [86.1K]
2 years ago
10

Help me pls! 8 - 5 1/3=?

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
3 0

Answer:

2 2/3

Step-by-step explanation:

8- 5 1/3

=8-16/3

=8/3

8/3=2 2/3

Nikitich [7]2 years ago
3 0

Step-by-step explanation:

2 2/3 that guy is. right ✅

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A machine makes two components; call them types A and B. It takes 250 seconds to switch production between the component types.
Alexus [3.1K]

Answer:

The average inventory depends on the manufacturing batch size.

Its formula is:

Inventory=\frac{n}{3n+250}

Step-by-step explanation:

The question is incomplete.

Question complete:

<em>"A machine makes two components, call them type A and B. It takes 250 seconds to switch production between the component types. During that time no production occurs. When in production, each unit of A or B requires 0.5 seconds to be completed. The two components, A and B are combined in an assembly process to make a final product, call it C. The assembly step can combine the two components into 1 unit every 2 seconds. What is the average inventory of B components?"</em>

We have two steps in this process: the manufacturing of A and B and the assembly process.

We are not told about the batch size, so we will treat that as a variable called n. This represents the amount of units (of A or B) that are manufactured per cycle.

Time (seconds) to manufacture n units of A and n units of B:

T_m=n*0.5+n*0.5+250=n+250

Time (seconds)to assemble n units of C

T_a=n*2=2n

Then the total time of the cycle is:

T_m+T_a=n+250+2n=3n+250

The average inventory of B is n units per cycle, which lasts (3n+250) seconds.

Inventory=\frac{n}{3n+250}

For a batch size of 100 units, the average inventory is:

I_{100}=\frac{100}{3*100+250}=\frac{100}{550}=  0.182\, units/second

For a batch size of 1,000 units, the average inventory is:

I_{1000}=\frac{1000}{3*1000+250}=\frac{1000}{3250}=  0.308\, units/second

5 0
3 years ago
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