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3 years ago

Did I do this Calculus problem correct?

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

7 0

Your writing is a bit messy and hard to follow (the integral part especially), but you have the correct steps and the correct final answer. Nice work.

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List all pairs of congruent angles. Then write the ratios of the corresponding side lengths in a statement of proportionality

PIT_PIT [208]

Answer:

Part A)

m<BDG=m<MPQ

m<DBG=m<PMQ

m<DGB=m<PQM

Part B) $\frac{BD}{MP}=\frac{DG}{PQ}=\frac{BG}{MQ}$

Step-by-step explanation:

we know that

If two triangles are similar, then the ratio of its corresponding sides is equal and its corresponding angles are congruent

Part A)

we have that

the congruent angles are

m<BDG=m<MPQ

m<DBG=m<PMQ

m<DGB=m<PQM

Part B) The ratio of its corresponding sides is equal to

$\frac{BD}{MP}=\frac{DG}{PQ}=\frac{BG}{MQ}$

8 0

3 years ago

What is the slope of the line 7x-9=y

andriy [413]

The slope is always the number next to the x. In this case it's 7 or 7/1

5 0

3 years ago

Read 2 more answers

Solve for x in the equation x2+10x+12=36

Snezhnost [94]

Answer:

x² + 10x + 12 = 36

x² +10x + 12-36 = 0

x² + 10x - 24 = 0

now by factorization;

x² + 12x - 2x - 24 = 0

x(x+12) -2(x+12) = 0

(x+12)(x-2) = 0

Now, x+12 = 0 and x-2 = 0

x = -12 and x = 2

x= -12, 2

Thus the values for x is -12 and 2.

8 0

4 years ago

Read 2 more answers

The histogram shows the weekly rates charged by different daycares for a 2-year-old child.

serious [3.7K]

Answer: the answer in c on edge

Step-by-step explanation:

8 0

4 years ago

What is the polar form of -3+ v3i?

Softa [21]

z=-3+√3i
a=-3,b=√3

$\\ \rm\Rrightarrow r=\sqrt{a^2+b^2}$

$\\ \rm\Rrightarrow r=\sqrt{(-3)^2+(\sqrt{3})^2}$

$\\ \rm\Rrightarrow r=\sqrt{9+3}$

$\\ \rm\Rrightarrow r=\sqrt{12}$

$\\ \rm\Rrightarrow r=2\sqrt{3}$

Find theta

$\\ \rm\Rrightarrow \theta=tan^{-1}(\dfrac{y}{x})$

$\\ \rm\Rrightarrow \theta=tan^{-1}(\dfrac{\sqrt{3}}{3})$

$\\ \rm\Rrightarrow \theta=tan^{-1}(\dfrac{-1}{\sqrt{3}})$

$\\ \rm\Rrightarrow \theta=\dfrac{5\pi}{6}$

Polar form

$\\ \rm\Rrightarrow r(cos\theta+isin\theta)$

$\\ \rm\Rrightarrow 2\sqrt{3}(cos\dfrac{5\pi}{6}+isin\dfrac{5\pi}{6})$

7 0

2 years ago