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Irina18 [472]
3 years ago
8

Choose yes or no to tell if the digit in the hundreds place is 1/10 the value of the digit in the thousand place. 8,556 , 6,855

, 5,568, 5,656.
Mathematics
2 answers:
Brut [27]3 years ago
6 0
The answer is yes cause it has to be between 1-10 no bigger than just in between 1-10
Tresset [83]3 years ago
3 0

Answer:

Option 3 - 5,568

Step-by-step explanation:

To find : Choose yes or no to tell if the digit in the hundreds place is \frac{1}{10} the value of the digit in the thousand place ?

Solution :

According to place value system,

Thousand    Hundred    Tens    Ones

1) Number 8556

Thousand value of number = 8000

Hundred value of number = 500

8000\times \frac{1}{10}=800

The digit in the hundreds place is not \frac{1}{10} the value of the digit in the thousand place.

2) Number 6855

Thousand value of number = 6000

Hundred value of number = 800

6000\times \frac{1}{10}=600

The digit in the hundreds place is not \frac{1}{10} the value of the digit in the thousand place.

3) Number 5568

Thousand value of number = 5000

Hundred value of number = 500

5000\times \frac{1}{10}=500

The digit in the hundreds place is \frac{1}{10} the value of the digit in the thousand place.

4) Number 5656

Thousand value of number = 5000

Hundred value of number = 600

5000\times \frac{1}{10}=500

The digit in the hundreds place is not \frac{1}{10} the value of the digit in the thousand place.

Therefore, Option 3 is correct.

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Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be​ ac
Likurg_2 [28]

For this problem, the most accurate is to use combinations


Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are nC_r = \frac{ n! }{r! (n-r)!}

n represents the amount of things you can choose and choose r from them


You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

P = \frac{_{117}C_3}{_{120}C_3}


Where _{117}C_3 is the number of ways to select 3 non-defective components from 117 non-defective components and _{120}C_3 is the number of ways to select 3 components from 120.

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So:

P = \frac{260130}{280840} = 0.927


Finally, the probability that at least one of the selected components is defective is:


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Pls help!!
erik [133]

Answer:

A

Step-by-step explanation:

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