Question

Simplify ="\frac{1}{2e} R + \frac{1}{2e} R" alt="\frac{1}{2e} R + \frac{1}{2e} R" align="absmiddle" class="latex-formula">

Answer 1

Answer:

$\frac{Rx + eR}{2ex}$

Step-by-step explanation:

You first calculate the product which is $\frac{R}{2e}$ +$\frac{1}{2x} R$ to $\frac{R}{2e} + \frac{R}{2x}$

Then write all numerators above the least common denominator ($2ex$)

Now you have your answer.