3 years ago

Help me again guys plz

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

6 0

I think it's letter C. 1/2 and 3/16

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You have less than 120 minutes to spend in the gym and in the pool. You want to spend less than 45 minutes in the gym and more t

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Spend 45 minutes in the gym, then spend the rest hour and 15 minutes in the pool.

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3 years ago

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sleet_krkn [62]

Step-by-step explanation:

I'll help you darling

a. B

b. 2.6 + x = 10.4

c. x = 10.4 - 2.6

= 7.8

d. This is to say before mia added the 2.6 litres of what the pitcher contained 7.8 litres of water already

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3 years ago

Please explain how to help me learn please

devlian [24]

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4 years ago

Karen had 7 items in her shopping cart with different prices. Her mean cost of these items was $4.02. At the register, she added

alukav5142 [94]

Answer:

the answer is D

Step-by-step explanation

if your adding more stuff to your shopping cart it does not matter what item it is it will always increase

7 0

3 years ago

Kala’s company makes solid metal balls for various industrial uses. A customer wants aluminum balls that have a diameter of 6 in

KiRa [710]

7,912.8 inch³ of aluminum is needed to make 70 metal balls.

Step-by-step explanation:

Step 1:

The area of a sphere is calculated by multiplying $\frac{4}{3}$ with π and the cube of the radius (r³).

In the given problem, the diameter is 6 inches. So the radius of the spheres is 3 inches.

The volume of a sphere, $V = \frac{4}{3} \pi r^{3} .$

So if r = 3 inches and π = 3.14,

$V = \frac{4}{3} (3.14) (3^{3}) = 113.04$ cubic inches.

So for a single aluminum ball, 113.04 inch³ of aluminum is needed.

Step 2:

If 113.04 inch³ of aluminum is used for 1 ball, then we multiply 70 with this value to determine the aluminum needed for 70 such balls.

The aluminum needed for 70 metal balls $= 70(113.04) = 7,912.8$ inch³.

So 7,912.8 inch³ of aluminum is needed to make 70 metal balls.

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4 years ago