Answer:
<em>p</em>(<em>x</em>) = 6(x + 2)² - 3
Step-by-step explanation:
This one requires a lot of thinking because since our <em>A</em><em> </em>is not 1 and how the quadratic equation looks, we need to think of a low number while "completing the square [½B]²". So, let us choose 2. We set it up like this:
6(x + 2)² → 6(x² + 4x + 4) → 6x² + 24x + 24
6x² + 24x + 24 - 3 → 6x² + 24x + 21 [TA DA!]
We know that our vertex formula is correct. Additionally, <em>-h</em> gives you the OPPOSITE terms of what they really are, and <em>k</em><em> </em>gives you the EXACT terms of what they really are. Therefore, your vertex is [-2, -3].
I am joyous to assist you anytime.
Answer:
The third one is 92
Step-by-step explanation:
Because of the order of operations you do 8x3 first. 8x3= 24. So now our equation would look like this... 80+24÷2. Now 24÷2=12. so now our equation looks like this... 80+12=?
80+12=92
Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)