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Valentin [98]
3 years ago
7

Linda West, a dental lab technician, pays three times as much

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

9514 1404 393

Answer:

  • vision: $13.50
  • dental: $40.50
  • health: $162.00

Step-by-step explanation:

Let d, v, h represent the costs of dental, vision, and health insurance, respectively. The cost relations are ...

  d = 3v . . . . . . . . . . . . . . . dental is 3 times vision

  h = 3(v +d) . . . . . . . . . . . health is 3 times vision and dental combined

  d + v + h = 9360 . . . . . annual premium

Substituting for h, we have ...

  d + v + (3(d +v)) = 9360

Substituting for d, we have ...

  3v +v +3(3v +v) = 9360

  16v = 9360

  v = 585

  d = 3v = 1755

  h = 3(d+v) = 7020

These are the total annual premiums. Linda pays 1/26 of 60% of this every two weeks. That fraction is 0.60/26 = 3/130.

a) Linda's biweekly vision insurance deduction is (585)(3/130) = $13.50

b) Linda's biweekly dental insurance deduction is (1755)(3/130) = $40.50

c) Linda's biweekly health insurance deduction is (7020)(3/130) = $162.00

_____

<em>Additional comment</em>

We know dental is 3v and health is 3(3v+v) = 12v = 4d. That is, once we find Linda's share of the biweekly vision premium, we can find the others by multiplying it by a suitable factor.

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For example:
8 positive counters plus 18 negative counters:

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8 0
3 years ago
A professor at a university wants to estimate the average number of hours of sleep students get during exam week. The professor
kotegsom [21]

Answer:

n=(\frac{1.64(6.995)}{1.939})^2 =35.003 \approx 36

So the answer for this case would be n=36 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =6.995 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =1.939 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

If we replace we have this:

n=(\frac{1.64(6.995)}{1.939})^2 =35.003 \approx 36

So the answer for this case would be n=36 rounded up to the nearest integer

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igomit [66]
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r2=1-√5
6 0
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Answer:

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