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KATRIN_1 [288]
3 years ago
14

HELLP BRAINLIEST!!! Could someone clarify something for me?? What is the expression that represents the area of the rectangle? D

o i solve this or do i just find the expression? Also could you help me solve the problem below?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0

Answer:

See below.

Step-by-step explanation:

The question doesn't ask you to find the area, it just ask for the expression that represents the area.

The area of rectangle is A=bh, where b and h are each of the side lengths.

Since we know the sides are (2x+7) and (5x+9), this means that the expression for the area of the rectangle is:

(2x+7)(5x+9)

To find the degree and classification, expand the factors:

=(2x+7)(5x+9)\\=(10x^2+18x+35x+63)\\=10x^2+53x+63

Thus, this is a second degree quadratic expression

And from Part A, when we multiplied (2x+7)(5x+9), we got another polynomial (10x^2+52x+63). Thus, this rerepresents the closure property of polynomials, where multiplying a polynomial by another gets another polynomial.

.

denis23 [38]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

Part A

(2x+7) ( 5x+9)

Foil

first 2x*5x = 10x^2

outer: 2x*9 = 18x

inner: 7*5x= 35x

last: 7*9 = 63

Add together

10x^2 +18x+35x+63

10x^2+53x+63

Part B

This is a second degree polynomial called a quadratic

Part C

When we multiply two polynomials together, we get another polynomial.  This is the closure property for multiplication of polynomials

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Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 < Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

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Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

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(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

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