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g100num [7]
2 years ago
13

A Car’s rectangular gas tank has dimensions 30 cm by 25 cm by 42 cm.

Mathematics
1 answer:
Alchen [17]2 years ago
8 0

Answer:

$4851

Step-by-step explanation:

rectangular prism volume = length x width x height

1 litre = 1000 cm³

cost = $per litre x litres

v = l x w x h

30cm x 25cm x 42cm = 31500cm³

litres = cm³ / 1000

31500cm³ / 1000 = 31.5 litres

31.5 x $154 = $4851

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If f(x)=6x^3-4 and g(x)=2x+2, find (f-g)(x)
Lerok [7]

Answer:

https://socratic.org/questions/if-f-x-6x-3-and-g-x-2x-2-find-f-g-x

Step-by-step explanation:

Go to this site. It has the correct answer

8 0
2 years ago
Factor the quadratic expression t^2 + 4t - 7
zepelin [54]

Answer:

Not factorable.

Step-by-step explanation:

We have a trinomial (3 terms). We factor by splitting the middle term 4t into factors of -7 (the last term) which add to 4.

-7 = 1 * -7

4t= 1t+-7t doesn't work

4t=-1t+7t doesn't work

This is not factorable.



7 0
3 years ago
PLEASE HELP I BEG YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
ruslelena [56]

Answer:

R1:   Given

R2:   Subtraction Property of Equality

R3:   Distribute Property

R4:   Addition Property of Equality

R5:   Division Property of Equality

Write a paragraph proof for the following conjecture: m∠1 + m∠2 = m∠4

Prove: m∠3 + m∠1 + m∠2 = 180°

Given: ∠1 + ∠2 = ∠ 4

∠4 + ∠3 must be 180° because they are supplementary

If ∠4 + ∠3 is 180, and ∠1 + ∠2 = ∠4, you can substitute ∠4 in the first equation for ∠1 + ∠2.

Hence, we arrive at the answer ∠1 + ∠2 + ∠3 = 180.

Plz mark brainliest:)

7 0
3 years ago
Normal distribution HELP
elena-14-01-66 [18.8K]

Answer:

0.0351478382 (To be precise)

Step-by-step explanation: Can I get brainliest? Thanks

1. Normal Distribution --> Z ~ (0,1^2)

2. Use normalcdf(lower bound, upper bound, μ, σ) function on a graphing calculator

P(Z≥103.53) = normalcdf(103.53, 1e99 [default], 80, 13)

P(Z≥103.53) ≈ 0.03

3. μ+σ ≈ 13.59% According to Z-distribution chart

80+13=93

So about 93 exceed only the top 16% (estimated answer not exact)

8 0
2 years ago
Suppose that the rate of return on stocks is normally dis-tributed with mean of 9% and a standard deviation of 3%. If I pick fiv
alisha [4.7K]

Answer:

The probability that at least two stocks will have a return of more than 12% is 0.1810.

Step-by-step explanation:

Let <em>X</em> = rate of return on stocks.

The random variable <em>X</em> follows a Normal distribution, N (9, 3²).

Compute the probability that a stock has rate of return more than 12% as follows:

P(X\geq 12)=1-P(X

**Use the <em>z</em> table for the probability.

The probability of a stock having rate of return more than 12% is 0.1587.

Now define a random variable <em>Y</em> as the number of stocks that has rate of return more than 12%.

The sample size of stocks selected is, <em>n</em> = 5.

The random variable <em>Y </em>follows a Binomial distribution.

The probability of a Binomial distribution is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...

Compute the value of P (X ≥ 2) as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{5\choose 0}(0.1587)^{0}(1-0.1587)^{5-0}-{5\choose 1}(0.1587)^{1}(1-0.1587)^{5-1}\\=1-0.4215-0.3975\\=0.1810

Thus, the probability that at least two stocks will have a return of more than 12% is 0.1810.

6 0
2 years ago
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