If we plot that point we find ourselves in QIV. The distance along the x axis is 4, and the distance down from that point is -3. If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle. We need its measure. Using Pythagorean's theorem,

and

. We see that c = 5. We need now to find the secant of that right triangle. Secant if the co-identity of cosine which is side adjacent over hypotenuse. That means that secant is the hypotenuse over the side adjacent. So our secant theta = 5/4
The correct answer is A: -1.8 + 5.4. Adding a negative is the same as subtracting.
Answer:
solutions at -1 and 11
Step-by-step explanation:
(-b ± √b²-4ac) / 2a
in this problem, a = 1, b = -10, c = -11
(10±√100-4(-1)(-11)) / 2(1) =
(10 + √144) / 2 = 22/2 = 11
(10 - √144) / 2 = -2 / 2 = -1
27.32 you divide 24.50 and 11.5. Then add what you get from that to 24.50
Cos θ=1/3
cos θ=sen (90-θ)
therfore:
sen (90-θ)=1/3
To chek
θ=arc cos 1/3=70.53º
sin (90-θ)=sin (90º-70.53º)=sin 19.47≈0.3333≈1/3