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kirill115 [55]
3 years ago
11

The length of a rectangle is three times its width. If the perimeter is at most 128cm, what is the greatest possible value for t

he width?
Mathematics
1 answer:
anastassius [24]3 years ago
3 0

Answer:

16 cm

Step-by-step explanation:

Let the width be x

The length will be 3 x since the length is three times the width

Perimeter=2(l+w) where l is length and w is width

By substituting 128 cm for perimeter, x for w and 3 x for l then

128=2(3x+x)

128=8x

x=\frac {128}{8}=16

Therefore, the width is 16 cm, the width is 16*3=48 cm

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\text{Let the number of boys be x and number of girls be y.}\\
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x+y=416 \ \ \ \ \ \ \ \ \ \ ......(i)\\
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\frac{x}{y}=\frac{7}{6}

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