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3 years ago

Find the first four (4) terms of the sequence if An=(4) an-1 and a1 =3

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

6 0

Answer:

3, 12, 48, 192

Step-by-step explanation:

To find the first 4 terms substitute n = 2, 3, 4 into the recursive formula, that is

a₂ = 4a₁ = 4 × 3 = 12

a₃ = 4a₂ = 4 × 12 = 48

a4 = 4a₃ = 4 × 48 = 192

Thus the first 4 terms of the sequence are 3, 12, 48, 192

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Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?

oee [108]

The answer is $\frac{x^{4/3}y^{3}}{3}$ .

The fraction is: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }$
Let's rewrite it: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }$

Since $\frac{x^{a} }{x^{b}} =x^{a-b}$ ,
then:
*** $\frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}$
*** $\frac{y^{-2} }{ y^{-5} }= y^{-2-(-5)} = y^{-2+5} = y^{3}$
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$\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}$

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3 years ago

Please answer #1 and #2

DIA [1.3K]

1)
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2)
(3zx^4) /(5+z) = 2y
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2 years ago

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3 years ago

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4 / 3 is equal to 12 / k<br> What does k equal?

Natali5045456 [20]

Answer:

k=9

Step-by-step explanation:

4/3 = 8/6 = 12/9

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3 years ago

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H(x)=-x^2-4 and I(x)=2x+3<br> H(I(s))

ICE Princess25 [194]

Easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
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3 years ago