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3 years ago

A proof should always begin with stating the given information. True False

Mathematics

2 answers:

const2013 [10]3 years ago

5 0

<span>A proof should always begin with stating the given information.
True</span>

Mila [183]3 years ago

5 0

True,,, usually mostly

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A small bar of gold measures 20 mm by 150 mm by 2 mm. One cubic milimeter of gold weighs about 0.0005 ounces. Find the volume in

Kay [80]

Answer:

= 3oz

Step-by-step explanation:

v = 20mm ×150mm ×2mm = 6000 mm^3

so, the weight is

6000 mm^3 × 0 .0005oz/1mm^3 = 3oz

6 0

2 years ago

I NEED HELP ASAP

DiKsa [7]

Length = 4w + 2

A = length x width
= (4w + 2) . w
= 4w^2 + 2w ft square

5 0

2 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago

WILL MARK THE BRAINLIEST!! PLEASE HELP If ∠1 = 3x, ∠2 = 5x + 18, and s ⊥ r, find m∠1. Question 5 options: A) 27° B) 63° C) 61° D

Yakvenalex [24]

Answer:

A. 27°

Step-by-step explanation:

Given that s is perpendicular to r, and <1 = 3x, <2 = 5x + 18, therefore:

m<1 + m<2 = 90°

3x + (5x + 18) = 90°

Solve for x using this equation

3x + 5x + 18 = 90

8x + 18 = 90

Subtract 18 from both sides

8x + 18 - 18 = 90 - 18

8x = 72

Divide both sides by 8

x = 9

Find m<1

m<1 = 3x

Plug in the value of x

m<1 = 3(9) = 27°

5 0

3 years ago

In the equation -2(2-r)=4(5-r) what is r?

valina [46]

$-2(2-r)=4(5-r)\\
-4+2r=20-4r\\
6r=24\\
r=4$

8 0

3 years ago