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2 years ago

Please help I have a quiz soon

Mathematics

1 answer:

Novay_Z [31]2 years ago

3 0

Answer:

The option that no represent a linear function is $f(x)=3^x$

Step-by-step explanation:

we know that

The graph of a linear function is a straight line

The equation of a linear function in slope intercept form is equal to

$f(x)=mx+b$

where

m is the slope

b is the y-intercept

<u><em>Verify each case</em></u>

option 1) we have

$f(x)=3x-2$

This option represent a linear function

where

m=3

b=-2

option 2) we have

$f(x)=x$

This option represent a linear function

where

m=1

b=0

This option represent a linear direct variation function

option 3) we have

$f(x)=3^x$

This option not represent a linear function

This option represent a exponential function

option 4) we have

$f(x)=3x$

This option represent a linear function

where

m=3

b=0

This option represent a linear direct variation function

You might be interested in

What is tan 330°? for algebra 2 with trig in it.

Alekssandra [29.7K]

Tan (330) = 0.133557

8 0

3 years ago

Use formulas to find the lateral area and surface area of the given prism. Round your answer to the nearest whole number.

tankabanditka [31]

Answer:

lateral area ≈ 668 m²

surface area ≈ 740 m²

Step-by-step explanation:

The lateral area of a triangular prism = perimeter of the base × height of the prism

lateral area = ph

where

p = perimeter of the base

h = height or altitude

Base edges are 8m , 9m and 12.04m and height is 23 m.

lateral area = ph

lateral area = (8 + 9 + 12.04) × 23

lateral area = 29.04 × 23

lateral area = 667.92 m²

lateral area ≈ 668 m²

Surface area

surface area = lateral area + 2B

where

B = area of it triangular bases

surface area = lateral area + 2B

surface area = 667.92 + 2(1/2 × base × height)

surface area = 667.92 + 2(1/2 × 8 × 9)

surface area = 667.92 + 2(1/2 × 72)

surface area = 667.92 + 2(36)

surface area = 667.92 + 72

surface area = 739.92

surface area ≈ 740 m²

8 0

2 years ago

You have 42 ft. of fencing (1 ft. segments) to make a rectangular garden. How much should each side be to maximize your total ar

Verizon [17]

Answer:

$Length=10.5\ ft$

$Width=10.5\ ft$

$Area=110.25\ ft^{2}$

Step-by-step explanation:

Let

x----> the length of the rectangular garden

y---> the width of the rectangular garden

we know that

The perimeter of the rectangle is equal to

$P=2(x+y)$

we have

$P=42\ ft$

$42=2(x+y)$

simplify

$21=(x+y)$

$y=21-x$ ------> equation A

Remember that the area of rectangle is equal to

$A=xy$ ----> equation B

substitute equation A in equation B

$A=x(21-x)$

$A=21x-x^{2}$ ----> this is a vertical parabola open downward

The vertex is a maximum

The y-coordinate of the vertex is the maximum area

The x-coordinate of the vertex is the length side of the rectangle that maximize the area

using a graphing tool

The vertex is the point $(10.5,110.25)$

see the attached figure

$x=10.5\ ft$

Find the value of y

$y=21-10.5=10.5\ ft$

The garden is a square

the area is equal to

$A=(10.5)(10.5)=110.25\ ft^{2}$ ----> is equal to the y-coordinate of the vertex is correct

6 0

2 years ago

Multiple choice please answer please

eduard

Answer: 33.85 mm

Step-by-step explanation:

Use trigonometry, tan equation

You are give the tan angle and adjacent side, you need to find the opposite side so

T A

Tan(72)= x/11

x= tan(72) x 11

x= 33.85

8 0

3 years ago

Read 2 more answers

Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c

nadya68 [22]

Answer:

$A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right]$ message SHOW_ME_THE_MONEY_

Step-by-step explanation:

The matrix

$A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\$

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message Decoded message message in letters by association

11 52 19 8 S H

-8 -9 15 23 O W

-13 -39 0 13 _ M

5 20 5 0 E _

12 56 20 8 T H

5 20 5 0 E _

-2 7 13 15 M O

9 41 14 5 N E

25 100 25 0 Y _

Then the message decoded is SHOW_ME_THE_MONEY_

3 0

2 years ago