The perimeter of triangle ABC is 24 units
Step-by-step explanation:
If a segment joining the mid points of two sides of a triangle, then
this segment is:
- Parallel to the third side
- Its length is half the length of the third side
In The triangle XYZ
∵ A is the mid point of XY
∵ B is the mid point of YZ
∴ AB = 
XZ
∵ XZ = 18 units
- Substitute the value of XZ in AB
∴ AB = × 18 = 9 units
∵ B is the mid point of YZ
∵ C is the mid point of XZ
∴ BC = XY
∵ AY = 7 units
∵ AY = XY
∴ XY = 2 × AY
∴ XY = 2 × 7
∴ XY = 14 units
∴ BC = × 14 = 7 units
∵ A is the mid point of XY
∵ C is the mid point of XZ
∴ AC = YZ
∵ BZ = 8 units
∵ BZ = YZ
∴ YZ = 2 × BZ
∴ YZ = 2 × 8
∴ YZ = 16 units
∴ AC = × 16 = 8 units
∵ The perimeter of a triangle = the sum of the lengths of its sides
∴ Perimeter Δ ABC = AB + BC + AC
∴ Perimeter Δ ABC = 9 + 7 + 8 = 24 units
The perimeter of triangle ABC is 24 units
Learn more:
You can learn more about triangles in brainly.com/question/5924921
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Answer:
(b) 21.4
Step-by-step explanation:
There are a couple of interesting relations regarding chords and secants and tangents of a circle. With the right point of view, they can be viewed as variations of the same relation, possibly making them easier to remember.
When chords cross inside a circle (as here), each divides the other into two parts. The product of the lengths of the two parts of one chord is the same as the product of the lengths of the two parts of the other chord.
Here, that means ...
7x = 10·15
x = 150/7 = 21 3/7 ≈ 21.4
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<em>Additional comment</em>
A secant is a line that intersects a circle in two places. (A tangent is a special case of secant where the two points of intersection are the same point.) When two secants meet outside the circle, there is a special relation between the lengths of the various line segments.
Consider the line segment from the point where the secants meet each other to the far intersection point with the circle. The product of that length and the length to the near intersection point with the circle is the same for both secants.
Here's the viewpoint that merges these two relations:
<em>The product of the lengths from the point of intersection of the lines with each other to the two points of intersection with the circle is the same for each line</em>.
(Note that when the "secant" is a tangent, that product is the square of the distance from the tangent point to the point of intersection with the other line--the distance to the circle multiplied by itself.)
Hey there!
When you see the decimal that looks like (0.3) this would be called a terminating decimal, which is a decimal that always have extra numbers at the end.
For example:
2.(3)
1.(67)
The number's that are in the parenthesis are the terminating numbers.
Hope this helps you!
~Jurgen<span />
This is a GCF problem,
find the GCF of 36 and 27. To do this, list out the factors for each number.
EX 36- 1×36, 2×18, so on and so on. Then do this for 27. The GCF will be the greatest factor. In this case, that is 9.
So there would be 9 groups because that is the greatest common factor.
there would be 4 roses in each group because 4×9= 36.
There are 3 carnations in each group because 9×3 =27.
So 9 groups with 4 roses and 3 carnations.
