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Margaret [11]
3 years ago
9

What is the measure of BC⏜ ? Enter your answer in the box. ° Circle with inscribed angle B D C. Angle B D C is 65 degrees.

Mathematics
2 answers:
Zigmanuir [339]3 years ago
6 0

Answer:

Minor arc BC - 130° (arc at which inscribed angle is subtended)

The major arc BC - 230°

Step-by-step explanation:

Angle BDC is inscribed angle subtended on the arc BC.

The measure of the angle BDC is 65°.

The Central Angle Theorem states that the central angle from two chosen points B and C on the circle is always twice the inscribed angle from those two points.

By the central angle theorem, the measure of central angle BOC (O is the center of the circle) has the measure of

2\cdot 65^{\circ}=130^{\circ}

Hence, the minor arc BC has the same measure as the central angle BOC that is 130°.

The major arc BC has the measure

360^{\circ}-130^{\circ}=230^{\circ}

Ganezh [65]3 years ago
3 0

Answer:

130

Step-by-step explanation:

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Step-by-step explanation:

Given : A rectangle 4 x 8 , a semicircle

Diagonal intersecting semicircle  

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<h3>Solution:</h3>

Angle AC make AB   α = ∠BAC

tan α = BC/AB = 4/8 = 1/2

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in Left side area  between square  and circle is split in 2 Equal parts

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Now find area AFG = area ΔAEF - sector EGF

area ΔAEF  

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area ΔAEF   = (1/2) 4√2 * 4 sin 8.13° = 1.6 sq unit

area  sector EGF  = (8.13/360)π4² = 1.135  sq unit

area AFG  = 1.6 - 1.135  = 0.465 sq unit

Area of Red part = 1.7168 - 0.465 sq unit

= 1.2518 sq unit

= 1.252  sq unit

= 1.25 sq unit.

Hope this helps!!

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