Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
Insertion mutation takes the T out and replaces it with an A.
Answer:
b. Increase in activity of glycogen phosphorylase.
Explanation:
Glycogen synthase exists in two forms which is phosphorylated form which is covalent modification of serine residues by ATP and dephosphoryated form which is obtained using phosphatase on phosphorylated form. Glycogen phophorylase catalyzes hydrolysis of glycogen which shortens glycogen molecules.
Answer:
(1) Red Blood Cell
(2) Enzymes
Explanation:
(1) Oxygenated Red Blood cells transport oxygen from the lungs through the body using the arteries as a channel of movement to all organs.
(2) Enzymes are proteins that catalyze chemical reaction in the digestion of food so as to break food down into a form which can be absorbed by the body.
<span>Specialized cells protect the human body from disease-causing microbes by producing chemicals that destroy the microbes. </span>
