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2 years ago

Given a polynomial f(x), if (x + 3) is a factor, what else must be true?

2 answers:

4 0

Thank you for posting your question here at brainly. Feel free to ask more questions.

The best and most correct answer among the choices provided by the question is f(-3) = 0.

Hope my answer would be a great help for you.

Rom4ik [11]2 years ago

4 0

Answer:

$f(-3)=0$

Step-by-step explanation:

we know that

The zero of a function is the value of x when the value of the function is equal to zero

In this problem

If $(x+3)$ is a factor of a polynomial

then

$x=-3$ is a zero of the polynomial

For $x=-3$ -------> $f(-3)=0$

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3 years ago

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Determine whether (2, - 1) and (-4, 2) satisfy the inequality 2x – 3y > 4.

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2 years ago

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product A.B = 0, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$

The answer is same from both the approaches.

So, the correct answer is:

C) Both

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2 years ago

When multiplying numbers with the same base you________ the exponents.

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Answer:

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Step-by-step explanation:

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2 years ago

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