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3 years ago

Write an expression to describe the sequence below. Use n to represent the position of a

Mathematics

1 answer:

MrRa [10]3 years ago

7 0

Answer:

n+1=x-1

Step-by-step explanation:

as n goes up, x decreases by 1 each time

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A hovercraft takes off from a platform.

lubasha [3.4K]

Answer:

81 meters.

Step-by-step explanation:

The height (in meters), h(x) of a hovercraft x seconds after takeoff, is modeled by:

$h(x)=-3(x-3)^2+108$

We are to determine its height at the time of takeoff.

Now, at the time of takeoff, x=0.

We substitute x=0 to solve for h.

$h(0)=-3(0-3)^2+108\\=-3(-3)^2+108\\=-3(9)+108\\=-27+108\\=81$ meters$

The height of the hovercraft at takeoff is 81 meters.

7 0

3 years ago

Read 2 more answers

A trinomial with a leading coefficient of 3 and a constant term of -5

Yakvenalex [24]

This is one example of a trinomial with a leading coefficient of 3 and a constant term of -5

4 0

3 years ago

Read 2 more answers

I got the first part but cant figure out the second, help would be appreciated

azamat

Answer:

see explanation

Step-by-step explanation:

look at the explanation& answer photo

6 0

2 years ago

How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.

kifflom [539]

<h2><u>QUADRATIC EQUATION</u></h2>

<h2> $\mathbb{ANSWER:}$ </h2>

$\bold{x = 0.8 \: } \: \sf \: {\color{grey}or} \: \: \: \bold{ x= \frac{4}{5} } \\$

$\bold{x = - 6}$

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

$\bold{Given \: Equation: \color{brown} 5x²+26x-24=0}$

First, add 24 to both sides.

$\bold{5x²+26x-24 - \purple{ 24} = 0 + \purple{24}}$

$\bold{ \implies \: 5x²+26x = 24 }$

Since the coefficient of 5x² is 5, divide both sides by 5.

$\bold{ \frac{5 {x}^{2} + 26x }{5} = \frac{24}{5} } \\$

$\bold{ \implies \: {x}^{2} + \frac{26}{5} x = \frac{24}{5} } \\$

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

$\bold{ {x}^{2} + \frac{26}{5} x + \frac{ \purple{169}}{ \purple{25}}= \frac{24}{5} + \frac{ \purple{169}}{ \purple{25}} } \\$

$\bold{ \implies \:\bold{ {x}^{2} + \frac{26}{5} x + \frac{ 169}{ {25}}= \frac{289}{25} } } \\$

Factor the left side.

$\bold{(x + \frac{13}{5} ) {}^{2} = \frac{289}{25} } \\$

Take square root.

$\bold{x + \frac{13}{5} = ± \: \sqrt{ \frac{289}{25} }} \\$

Then, add (-13)/5 to both sides.

$\bold{x + \frac{13}{5} + \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \: \sqrt{ \frac{289}{25}}} \\$

$\bold{ \: x = \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\$

$\implies \: \underline{ \boxed{ \bold{ \frac{4}{5} } \sf \: \: or \: \: \bold{ x = - 6}}} \\$

_______________❖_______________

3 0

2 years ago

Read 2 more answers

A jogger goes 1.5km west and then turns south.If the jogger finishes 1.7 km from the starting point,how far south did the jogger

kakasveta [241]

Hello!

You can use the Pythagorean Theorem to solve this

$a^{2} + b^{2} = c^{2}$

c is the hypotenuse
a and b are the legs

Put in the values you know

$1.5^{2} + b^{2} = 1.7^{2}$

Square the numbers

$2.25+ b^{2} =2.89$

Subtract 2.25 from both sides

$b^{2} =0.64$

Take the square root of both sides

b = 0.8

The answer is 0.8km

Hope this helps!

6 0

3 years ago