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laiz [17]
2 years ago
5

2) Which expression is equivalent to: y•y3•y2

Mathematics
1 answer:
Nastasia [14]2 years ago
3 0

Answer:

y^6

Step-by-step explanation:

When multiplying terms with exponents that have the same base, the rule is to add the exponents. y * y^3 * y^2 = y^(1 + 3 + 2). (remember that y has a hidden exponent of 1, we just don't write that because it is redundant and unnecessary). y^(1 + 3 + 2) = y^6

hope this helps! <3

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A quadratic equation ax^2+bx+c=0 has -11 and 4 as solutions. Find the values of b and c if the value of a is 1 (hint, use zero f
Alina [70]

Answer:

b = 7, c = -44

Step-by-step explanation:

If the quadratic equation has the solutions -11 and 4, the two factors are:

(x+11)(x-4)=0

Since when we use the zero factor property we get

x+11=0 ⇒ x= -11

x-4=0 ⇒  x=4

Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.

Now we develop the multiplications between parenthesis:

(x+11)(x-4)=0\\x^2-4x+11x-44=0\\x^2+7x-44=0

So b is the number that accompanies the x: b = 7

and c is the independent number: c = -44

3 0
3 years ago
Find the value of x. <br><br> A. 10 <br> B. 15 <br> C. 20 <br> D. 25
Ira Lisetskai [31]

Answer:

(5x+13)+(3x+7)=180°

5x+3x=180°-7°-13°

8x=160°

x=160/8

x=20°

option C is correct

6 0
3 years ago
Can someone please help me it would mean a lot
Dimas [21]

Answer:3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
2x - 3y = -1<br> y = x - 1
Viktor [21]
Here’s how you would work it out

3 0
3 years ago
The line segment has an endpoint (5,-6) and the midpoint is (-2,3). Find the other point.
gavmur [86]

Answer:

(-9,12)

Step-by-step explanation:

Endpoint\:= (5,-6) = x_1,y_1\\Midpoint = \: (-2,3)=x\:,y\\\\x = \frac{x_1+x_2}{2}\\\\ -2 = \frac{5+x_2}{2} \\-4 = 5+x_2\\-4-5=x_2\\-9 =x_2\\\\y = \frac{y_1+y_2}{2} \\\\3 = \frac{-6+y_2}{2} \\6 = -6+y_2\\6+(6)=y_2\\6+6=y_2\\12=y_2\\x_2 ,y_2=(-9,12)

4 0
3 years ago
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