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3 years ago

15

1/7÷5/2=? plzzzz help

1 answer:

daser333 [38]3 years ago

4 0

When dividing fractions, you have to switch the second fraction and multiply them.
So, like this:
1/7 x 2/5
Would equal
2/35

You might be interested in

(2x^2-5x+1)+(x^2-x-4)

maksim [4K]

Answer:

3x^2-6x -3

Step-by-step explanation:

(2x^2-5x+1)+(x^2-x-4)

we sum all coefficient according to the exponent of the variable

2x^2-5x+1+x^2-x-4 = 3x^2-6x -3

5 0

3 years ago

(10 POINTS IF YOU ANSWER) a rectangular garden measures 5 feet by 4 feet. The length and width are both increased by the same am

WINSTONCH [101]

I think they both increased by 3 and the new dimensions is 8 ft by 7 ft

4 0

3 years ago

Read 2 more answers

Ameeta finished 12 math problems. David finished 3 times as many. How many more math problems did David finish than Ameeta?

Volgvan

Answer:
david finished 24 problems more than ameetha
Step-by-step explanation:
<em>problems finished by ameetha = 12 problems</em>
<em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36</em>
<em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =</em>
<em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24 </em>
<em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24 so David finished 24 problems more than ameetha</em>

8 0

3 years ago

Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced

Sati [7]

Answer:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

Step-by-step explanation:

$\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls}$ , $(denoted \:W_1, W_2, \:and\: W_3)$

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

The tree diagram of this event is also attached.

6 0

3 years ago

Can you help stuck on this question for a while

stepladder [879]

Answer:

Option B

Step-by-step explanation:

Length of the rectangular sand box is given by the function,

F(x) = 3x³ + 6x - 2

Width of the sand box is represented by the function,

W(x) = 2x² - 4

Area function for the sand box will be,

Area of a rectangle = Length × Width

F(x) × W(x) = (3x³ + 6x - 2)(2x² - 4)

= 2x²(3x³ + 6x - 2) - 4(3x³ + 6x - 2)

= 6x⁵+ 12x³ - 4x²- 12x³- 24x + 8

= 6x⁵- 4x²- 24x + 8

Therefore, Area function will be represented by a polynomial degree of 5.

Option B will be the answer.

3 0

3 years ago