Hi! You don't actually need to graph this nor find the intersection in order to know the answer. Through the process of elimination we can rule out incorrect answers.
Firstly, we express both equations with y on the left hand side since all choices are in that form:


Knowing these, we can immediately rule out options a, c, and d since they have the wrong equations. This will leave us with option b.
You can verify if the point of intersection provided in option b is true by plugging in the values of x and y to both equations (you will find that it is indeed true).
ANSWER: b. <span>picture of coordinate plane with line y equals negative 2x minus 1 and line y equals negative 3 halves x minus 3. They intersect at 4, negative 9.</span>
Hello!
If all her shots were 3 pointers we will just divide
24÷3=8
Wendy made 8 baskets.
I hope this helps!
Answer:
9 X 15 = $135
Step-by-step explanation:
Multiply the equation.
Answer:

Step-by-step explanation:
Let <em>A</em> be the event of getting an odd number.
<em>P(A)</em> be the probability of getting an odd number.
Total odd numbers here are 6 i.e. 
Here, total numbers in the game are 12 i.e
.
Formula for probability of an <em>event E</em> can be observed as:


Let <em>B</em> be the event of getting 11.
<em>P(B)</em> be the probability of getting 11.
Total number of possible cases is 1.

is the probability that we get 11 and an odd number.
Possible number of cases = 1

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

Hence, P(B/A) = 
D) the answers growth because when the number 7 (in that position) is raised to a power it will grow at the rate of 7 to the power of (x)