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2 years ago

What’s the area? For this

Mathematics

1 answer:

ZanzabumX [31]2 years ago

7 0

to figure out the area you have to use the formula 1/2 base times height.

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3 years ago

You have a wire that is 38 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Drupady [299]

Answer:16.71 cm

Step-by-step explanation:

Given

Length of wire L=38 cm

One piece is bent in the form of square and another in the form of circle

let x be the length of circle

therefore length of square side $\frac{38-x}{4}$

A=total area of square and circle

radius of circle $r=\frac{x}{2\pi }$

area of circle $A_c=\pi r^2=\pi \times (\frac{x}{2\pi })^2$

Area of square $A_s=(\frac{38-x}{4})^2$

$A=\pi \times (\frac{x}{2\pi })^2+(\frac{38-x}{4})^2$

To get the minimum value of A we get

$\frac{\mathrm{d} A}{\mathrm{d} x}=\frac{2x}{4\pi }-\frac{2(38-x)}{16}$

$\frac{\mathrm{d} A}{\mathrm{d} x}=0$

$\frac{x}{4\pi }=\frac{38-x}{16}$

$x=\frac{38\pi }{4+\pi }$

Therefore circumference of circle

$x=\frac{38\pi }{4+\pi }=\frac{119.396}{7.142}=16.717 cm$

8 0

2 years ago

3n² + 2n - 8=0<br> Solve each equation with the quadratic formula

8_murik_8 [283]

Answer:

-2,4/3

Step-by-step explanation:

ax²+bx+c=0

$x=\frac{-b \pm\sqrt{b^2-4ac} }{2a} \\3n^2+2n-8=0\\n=\frac{-2\pm\sqrt{2^2-4*3*(-8)} }{2*3} \\n=\frac{-2 \pm \sqrt{4+96}}{6} }\\n=\frac{-2 \pm 10}{6} \\n=\frac{8}{6} =\frac{4}{3}\\or~n=\frac{-12}{6}=-2$

8 0

2 years ago