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3 years ago

Problem: -7(2)+y=60, so where do I start?

Mathematics

2 answers:

aev [14]3 years ago

4 0

-7(2)+y=60
-14+y=60
y=60+14
Y=74

VARVARA [1.3K]3 years ago

4 0

First simplify the left side of the equation:
-7(2)+y=60 -> -14+y=60
then you want to get y by it's self:
-14+y=60
-14 -14
------------------=> y=60-14
now simplify the right side of the equation:
y= 46

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quester [9]

Number of registrations a website received during July = 2500

Number of registrations a website received during August = 2245

Number by which the registrations decreased :

$=\tt 2500 - 2245$

$=\tt 255$

Thus, the registrations decreased by 255.

Let x be the perrcentage of decrease.

Which means :

$=\tt 255 = \frac{x}{100} \: of \: 2500$

$= \tt255 = \frac{x \times 2500}{100}$

$=\tt 255 = \frac{2500x}{100}$

$= \tt255 \times 100 = 2500x$

$= \tt25500 = 2500x$

$=\tt \frac{25000}{2500} = x$

$\color{plum} =\tt \bold{10.2\%}$

▪︎Thus, the percentage of decrease in the number of registered members = 10.2%

5 0

3 years ago

Im so lost, please help me asap

almond37 [142]

Answer:

it's so simple ....

x + 141 = 135

x = 135 - 141

x = -6

it means ur answer is a

8 0

3 years ago

Marcos purchased a sail boat for $56,900. He anticipates each year the boat will decrease in value by 8.1% from the previous yea

Varvara68 [4.7K]

Answer: $56,900\left( 0.919\right)^x$

Step-by-step explanation:

Given

Marcos purchased a sailboat for $\$56,900$

Each year the boat will decrease in value by $8.1\%$

After 1 year it is

$\Rightarrow 56,900-56,900\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\\$

after another year it becomes

$\Rightarrow 56,900\left( 1-0.081\right)-56,900\left( 1-0.081\right)\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\cdot \left( 1-0.081\right)\\\Rightarrow 56,900\left( 1-0.081\right)^2$

After $x$ years it is

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3 years ago

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DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

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Time cannot be negative

Therefore,

t < 6.61

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6 0

3 years ago

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Answer:

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Let us assume the water flows into the rank for x minutes.

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Water flows out at 5 gal/min, therefore in x minute the amount of water in the tank = 1000 + 10x - 5x = 1000 + 5x

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7 0

3 years ago