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Otrada [13]
3 years ago
12

Compare the hydronium ion concentration of the solution having a ph of 2.0

Chemistry
1 answer:
wel3 years ago
8 0
PH is a scale used to measure the acidity or alkalinity of an aqueous solution. It can be used to calculate the amount of hydronium ions in the solution. It is expressed as the negative logarithm to the base 10 of the concentration. 

pH = -log [H+]
2.0 = -log [H+]
[H+] = 0.01 M
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forsale [732]
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7 0
3 years ago
You mix 125 mL of 0.170 M with 50.0 mL of 0.425 M in a coffee-cup calorimeter, and the temperature of both solutions rises from
kondaur [170]

Here is the correct question

You mix 125 mL of 0.170 M CsOH with 50.0 mL of 0.425 M HF in a coffee-cup calorimeter, and the temperature of both solutions rises from 20.20 °C before mixing to 22.17 °C after the reaction. What is the enthalpy of reaction per mole of ? Assume the densities of the solutions are all 1.00 g/mL, and the specific heat capacities of the solutions are 4.2 J/g · K. Enthalpy of reaction = kJ/mol

Answer:

75.059 kJ/mol

Explanation:

The formula for calculating density  is:

density = \frac{mass}{volume}\\

Making mass the subject of the formula; we have :

mass = density × volume

which can be rewritten as:

mass of the solution =  density × volume of the solution

= 1.00 g/mL × (125+ 50 ) mL

= 175 g

Specific heat capacity = 4.2 J/g.K

∴ the energy absorbed is = mcΔT

= 175 × 4.2 × (22.17 - 20.00) ° C

= 1594.95 J

= 1.595 J

number of moles of CsOH =  \frac{125}{1000} *100

= 0.2125 mole

Therefore; the enthalpy of the reaction = \frac{Energy \ absorbed }{number \ of \ moles}

= \frac{1.595}{0.02125}

= 75.059 kJ/mol

5 0
3 years ago
A volume of 40.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
Anni [7]

<u>Answer:</u> The concentration of KOH solution is 1.215 M

<u>Explanation:</u>

For the given chemical equation:

2KOH(aq.)+H_2SO_4(aq.)\rightarrow K_2SO_4(aq.)+2H_2O(l)

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50M\\V_1=16.2mL\\n_2=1\\M_2=?M\\V_2=40.0mL

Putting values in above equation, we get:

2\times 1.50\times 16.2=1\times M_2\times 40.0\\\\M_2=\frac{2\times 1.50\times 16.2}{1\times 40.00}=1.215M

Hence, the concentration of KOH solution is 1.215 M

3 0
4 years ago
In the reaction Fe2O3 + 3CO a 2Fe + 3CO2, 10 moles of solid iron and 15 moles of carbon dioxide are produced from 5 moles of iro
Schach [20]

Answer:

Ratio is 3:2

3CO = 2Fe or 1.5 CO = 1 Fe

Explanation:

Fe2O3 + 3CO = 2Fe + 3CO2

Fe2O3 = Iron (|||) oxide

CO = Carbon monoxide

Fe = Solid Iron

CO2 = Carbon dioxide

Excellent is already balanced.

10 Moles Fe and 15 Moles of CO2

5 Moles Fe2O3 + 15 Moles 3CO = 10 Moles Fe + 15 Moles 3CO2

What is the ratio of carbon monoxide to solid iron

Ratio is 3:2 or 1.5 CO = 1 Fe

5 0
3 years ago
English
alisha [4.7K]
The answer is 250 cm^3.
5 cm x 5 cm x 10 cm = 250 cm^3
5 0
4 years ago
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