Answer:
The number of moles of salt in one tablespoon is = <u>0.11 mole</u>
<u>Grams </u>cancel each other.
Explanation:
<u>Moles</u> : It is the unit of quantity . It is the mass of the substance present in exactly 12g of C-12.
<u>Moles Calculation:</u>
Given mass = 6.37 gram
Molar mass = 58.5 g/mol
= 0.1088
= 0.11 mole
<u>Units calculation</u>
<u>g ang g cancels each other </u>
moles = moles
<u>Hence unit = gram (g ) cancel each other.</u>
Answer: The answer is D. This has a Carboxylic Acid group, and is acetic acid, or Ethanoic Acid.
ALWAYS LOOK for the Functional Group in question.
A. Would likely not stay in water, or at least not be acidic, for it is butane gas.
B. Is 1-propanol, and alcohols are not acidic as a rule. Certainly not in water.
C. This is an Ether. It will not give up an H+, it it not an acid.
E. This functional group is an amine, which is more “base” like, since the lone pairs of the Nitrogen atom would tend to attract a H+.
Answer:
111.68 g
Explanation:
Given data:
Mass of HgS needed = ?
Mass of CaS produced = 26.0 g
Solution:
Chemical equation;
4HgS + 4CaO → 4Hg + 3CaS + CaSO₄
Number of moles of CaS:
Number of moles = mass/molar mass
Number of moles = 26 g/ 72.143 g/mol
Number of moles = 0.36 mol
Now we will compare the moles of HgS with CaS.
CaS : HgS
3 : 4
0.36 : 4/3×0.36 = 0.48 mol
Mass of HgS:
Mass = number of moles × molar mass
Mass = 0.48 mol × 232.66 g/mol
Mass = 111.68 g
Answer:
D they are quickly replenished. I get this question a good bit so i know the answer.
Explanation:
Answer:b
Explanation:
From the question, the stoichiometry of the balanced reaction equation showed that 180gof glucose give 134.4L of CO2. Then we are given to find the volume of carbon IV oxide given off by 126g of glucose. This is done as shown in the image by relating what is given to the stoichiometry of the balanced reaction equation to obtain the answer as shown.
