In the reaction Fe2O3 + 3CO a 2Fe + 3CO2, 10 moles of solid iron and 15 moles of carbon dioxide are produced from 5 moles of iro
1 answer:
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Answer:
Oxidized and reducing agent: manganese.
Reduced and oxidizing agent: mercury.
Explanation:
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In this case, for the reaction:
We keep in mind that the species that increase the oxidation state is the oxidized one whereas the one that decrease the oxidation state is the reduced one; therefore manganese is the oxidized one as well as the reducing agent because it goes from 0 to +2 and mercury the reduced one as well as the oxidizing agent because it goes from 2+ to 0.
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Answer:
1. Hydrogen Iodide
2. 6 molecules of Hydrogen Iodide
3. Iodine is the limiting reagent
Explanation:
The image of the illustration in the question has been attached:
1. The illustration represents a mixture of hydrogen ( light blue ) and iodine ( purple )
H₂ + I₂ ---> 2HI
This forms hydrogen iodide.
2. In the given illustration, 6 product molecules of Hydrogen Iodide. This is indicated in the box on the right side of the illustration.
3. The limiting reagent is the reactant that determines how much of the products are made. It is the substance that is totally consumed when the chemical reaction is completed. In the box on the right side of the illustration, you will see that hydrogen which is indicated by blue is in excess. The limiting reagent is the one that is completely consumed which is the iodine.
Answer:
Explanation:
A chemical formula can be defined as a notation that is used to show which element and how many is contained in a chemical compound.
Also, in chemistry, the sum of charges of the anion and the cation of any ionic compound is always equal to zero.
A chemical equation is considered to be balanced when the amount of reactants on the left is equal to the amount of products on the right.
Therefore;
[2]FeBr3 + [3]Na2S → [1]Fe2S3 + [6]NaBr
In the above chemical equation, we will balance the reactants in the chemical equation with the smallest coefficients possible;
Two (2) moles of Iron (III) Bromide reacts with two (2) moles of Sodium Sulfide to form Iron (III) Sulfide and Sodium Bromide.