Answer:
All of the above processes have a ΔS < 0.
Explanation:
ΔS represents change in entropy of a system. Entropy refers to the degree of disorderliness of a system.
The question requests us to identify the process that has a negative change of entropy.
carbon dioxide(g) → carbon dioxide(s)
There is a change in state from gas to solid. Solid particles are more ordered than gas particles so this is a negative change in entropy.
water freezes
There is a change in state from liquid to solid. Solid particles are more ordered than liquid particles so this is a negative change in entropy.
propanol (g, at 555 K) → propanol (g, at 400 K)
Temperature is directly proportional to entropy, this means higher temperature leads t higher entropy.
This reaction highlights a drop in temperature which means a negative change in entropy.
methyl alcohol condenses
Condensation is the change in state from gas to liquid. Liquid particles are more ordered than gas particles so this is a negative change in entropy.
Answer:
Explanation:
Hello!
In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:
Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:
It means we can compute the final density as shown below:
Now, we plug in to obtain:
Regards!
Answer:
Tc^(+7) - 2.35*10^-5M
PO4(^-3) - 5.50*10^-5M
Explanation:
Tc3(PO4)7 <---> 
1 mol 3 mol 7 mol
7.85 X 10^-6 M 3*7.85*10^-6M 7*7.85*10^-6M
2.35*10^-5M 5.50*10^-5M
Answer:
5.1563867 × 10-9 miles
hope it helps
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Answer:
can you add the answer choices
Explanation:
