Answer:
F = 8066.67 N
Explanation:
The extra force exerted on the bottom of the jug can be expressed as the pressure generated by the cork multiplied by the area of the bottom. We can also obtain the Pressure P by dividing the force F1 applied to the cork by it's area A1.
Thus;
F = PA2 = (F1/A1) x (A2)
F = (F1/(πd1²/4)) x (πd2²/4)
π/4 will cancel out to give;
F = F1(d2/d1)²
F = 150(16.5/2.25)
F = 8066.67 N
Answer:
The correct option is;
The index of refraction of the second medium is lower
Explanation:
The index of refraction of a material indicates the magnitude of the optical density of a material. The index of refraction or the refractive index, n, are indices (ratio) of the speed of light through an optically dense medium relative to the speed of light through a vacuum.
The definition of the refractive index is the number of times light travelling through a medium would be slower than light travelling through vacuum
Therefore, the index of refraction of a second medium that is less optically dense than a first medium from which light originates and travels through it would be lower than the index of refraction of the first medium
Remember opposites attract and same charges repel each other.
Object A= negatively charged.
Object A and B attract so B must be positively charged.
Object B and C repel so because B is positively charged C must also be positively charged.
Object C and D attract and because C is positively charged, D must be negatively charged.
Answer:
2583.9 N/C
Explanation:
Parameters given:
Outer diameter = 14 cm
Outer radius, R = 7cm = 0.07m
Inner diameter = 7 cm
Inner radius, r = 3.5 cm = 0.035m
Charge of washer = 8 nC = 8 * 10^(-9)C
Distance from washer, z = 33 cm = 0.33m
The electric field due to a washer (hollow disk) is given as:
E = k * σ * 2π [ 1 - z/(√(z² + R²)]
Where σ = charge per unit area
σ = q/π(R² - r²)
σ = 8 * 10^(-9) /(π*(0.07 - 0.035)²)
σ = 2.077 * 10^(-6) C/m²
=> E = 9 * 10^9 * 2.077 * 10^(-6) * 2π * [1 - 0.33/(√(0.33² + 0.07²)]
E = 117.467 * 10^3 * (1 - 0.978)
E = 117.467 * 10^3 * 0.022
E = 2583.9 N/C
