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4 years ago

Which is a true statement about a series circuit?

Physics

1 answer:

vaieri [72.5K]4 years ago

6 0

the answer is B your welcome

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What is called the process of finding exact quantity of a substance?

Tema [17]

Answer:

Measurement is called the process of finding exact quantity of a substances.

7 0

2 years ago

A body of mass 8 kg moves in a (counterclockwise) circular path of radius 10 meters, making one revolution every 10 seconds. You

Sav [38]

Answer:

Centripetal force is equal to 31.55 N

Explanation:

We have given mass of the body m = 8 kg

Radius of the circular path r = 10 m

It is given that it makes 1 revolution in 10 seconds

Distance traveled in 10 seconds is equal to $d=2\pi r=2\times 3.14\times 10=62.8m$

Velocity is equal to $velocity=\frac{distance}{time}=\frac{62.8}{10}=6.28m/sec$

We have to find the centripetal force

Centripetal force is equal to $F=\frac{mv^2}{r}=\frac{8\times 6.28^2}{10}=31.55N$

So centripetal force will be equal to 31.55 N

8 0

3 years ago

Plz help i need answers to all these questions

Eduardwww [97]

Answer:

1) The net force is 5 N. The box is accelerating 10 m/s

2) The net force is 6.986 N. It is accelerating. Normal Force is 16.986

Explanation:

1) 20 N forward - 15 N backwards = a net force of 5 N

Acceleration: Acceleration = Net Force * Mass ( derived from Force = mass * acceleration).

a = 5 N / 2 kg

a= 2.5 m/s^2

8 0

3 years ago

If a display has a dynamic range of 20 dB and the smallest voltage it can handle is 200 mV, then the largest voltage it can hand

DedPeter [7]

Answer:

The largest voltage is 0.02 V.

(d) is correct option.

Explanation:

Given that,

Range = 20 dB

Smallest voltage = 200 mV

We need to calculate the largest voltage

Using formula of voltage gain

$G_{dB}=10 log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})$

$20 =10 log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})$

$2=log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})$

$10^2=\dfrac{V_{out}^2}{V_{in}^{2}}$

$\dfrac{V_{out}}{V_{in}^}=10$

$V_{in}=\dfrac{V_{out}}{10}$

$V_{in}=\dfrac{200}{10}$

$V_{in}=20\ mV$

$V_{in}=0.02\ V$

Hence, The largest voltage is 0.02 V.

8 0

3 years ago

A man starts from rest and accelerates at 4.00 m/s2. If he covers a distance of 525 m, how long does he accelerate?

rosijanka [135]

Answer:

16.2 s

Explanation:

Given:

Δx = 525 m

v₀ = 0 m/s

a = 4.00 m/s²

Find: t

Δx = v₀ t + ½ at²

525 m = (0 m/s) t + ½ (4.00 m/s²) t²

t = 16.2 s

5 0

3 years ago