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2 years ago

Which of the moon's properties prevents it from being pulled inward by Earth?

Physics

2 answers:

likoan [24]2 years ago

8 0

Answer:

O inertia

Explanation:

The moon's property that prevents it from being pulled inward by the Earth is called it's inertia.

Every object in the universal space have gravitational force of attraction to one another due to their masses.

An inertia is the reluctant of a body to move or the tendency of it to remain in constant motion.

Inertia entails the property of objects to remain at rest or continue in uniform motion.

As the force of gravity acts between the earth and the moon, inertia keeps a body in constant position.

allsm [11]2 years ago

4 0

The answer is Inertia

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) A satellite of mass m has an orbital period T when it is in a circular orbit of radius R around the earth. If the satellite in

Mrrafil [7]

Answer:

A) T.

Explanation:

Kepler's third law states that the orbital period (T) of a satellite is related with the radius (R) and the mass of the object (M) it orbits:

$T=\frac{2\pi R^{\frac{3}{2}}}{\sqrt{GM}}$

So the orbital period is independent of the mass of the satellite, that means no matter the mass every satellite at a radius R around the earth have an orbital period A.

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3 years ago

niobium metal becomes a superconductor when cooled below 9 k. its superconductivity is destroyed when the surface magnetic field

Furkat [3]

Niobium wire with a 2.60 mm diameter has a maximum current capacity of 500 A while still remaining superconducting.

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5 0

9 months ago

The rest deltoid row is a back exercise true or false

bixtya [17]

False because your deltoids are in your shoulders not your back

3 0

3 years ago

A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres

Lemur [1.5K]

Answer:

$V_2 = 0.125 m^3$

Work done = = 5 kJ

Explanation:

Given data:

volume of nitrogen $v_1 = 0.08 m^3$

$P_1 = 150 kPa$

$T_1 = 200 degree celcius = 473 Kelvin$

$P_2 = 80 kPa$

Polytropic exponent n = 1.4

$\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}$

putting all value

$\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}$

$\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS$

polytropic process is given as

$P_1 V_1^n = P_2 V_2^n$

$150\times 0.08^{1.4} = 80 \times V_2^{1.4}$

$V_2 = 0.125 m^3$

work done $= \frac{P_1 V_1 -P_2 V_2}{n-1}$

$= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}$

= 5 kJ

4 0

3 years ago

How much heat Q H QH does a heat pump with a coefficient of performance of 2.10 2.10 deliver when supplied with 1.82 kJ 1.82 kJ

valina [46]

The operating coefficient or performance coefficient of a heat pump is the ratio between the heating or cooling provided and the electricity consumed. The higher coefficients are equivalent to lower operating costs. The coefficient can be greater than 1, because it is a percentage of the output: losses, other than the thermal efficiency ratio: input energy. Mathematically can be written as,

$\text{Coefficient of performance} = \frac{\text{Heat extracted}}{\text{Electrical energy supplied}}$

$COP = \frac{Q}{E}\rightarrow Q =COP\times E$

Replacing,

$Q = 2.1\times 1.82kJ$

$Q = 3.822kJ$

Therefore the heat is 3.822kJ

4 0

2 years ago