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VashaNatasha [74]
3 years ago
8

A billiard ball travels 23 cm in the positive direction , hits the cushion and rebounds in the negative direction , and Finally

comes to rest 8.0 cm behind its orbital position.
What’s the displacement of the ball?
Physics
1 answer:
wel3 years ago
4 0

Explanation :

Displacement refers to the distance between the final and the initial position. Hence the displacement of the ball will be the difference between the initial and the final displacement.

Let the initial position be 0.

Final position = 8 cm

So the difference between initial position and final position = 0 – 8 = - 8 cm.

So the billiard ball comes to rest 8.0 cm behind its orbital position.

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Interstellar Dust

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In the solar system Interstellar dust is a type of cosmic dust and unlike Interstellar gas they have large dust particles enabling them to block visible light. Unlike smoke and fog, they contain large number of closely packed clumps of atoms and molecules

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While no one knows why, astronomers do now know that the solar nebula has ___________?
iris [78.8K]
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A barge floating in fresh water (p = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and height H
Karolina [17]

Answer:

a) \Delta m = 330000\,kg, b) h = 1.268\,m

Explanation:

a) According the Archimedes' Principle, the buoyancy force is equal to the displaced weight of surrounding liquid. The mass of the coal in the barge is:

\Delta m \cdot g = \rho_{w}\cdot g \cdot \Delta V

\Delta m = \rho_{w}\cdot \Delta V

\Delta m = \left(1000\,\frac{kg}{m^{3}} \right)\cdot (550\,m^{2})\cdot (1.05\,m-0.45\,m)

\Delta m = 330000\,kg

b) The submersion height is found by using the equation derived previously:

\Delta m = \rho_{w}\cdot \Delta V

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The final submersion height is:

h = 1.268\,m

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A compound is found to have a molar mass of 598 g/mol. if 0.0358 g of the compound is dissolved in enough water to make 175 ml o
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π=iMRT

Where, π is Osmotic pressure,
i=1 for non-electrolytes,
M is molar concentration of dissolved species (units of mol/L)
R is the ideal gas constant = 0.08206 L atm mol⁻¹K⁻¹,
T is the temperature in Kelvin(K),

Here, to calculate M convert into standard units mg tog, ml to L, c to Kelvin
M= (\frac{35.8}{598} *10⁻³ )/ 0.175 =(5.987 *10⁻⁵)mol / 0.175L = 34.21*10⁻⁵ mol/L

π=iMRT=(1)*(34.21*10⁻⁵)*(0.08206)*(298.15)=837×10⁻⁵= 8.37×10⁻³ atm
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3 0
3 years ago
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