Question

What is the value of x in the equation 2(x – 3) + 9 = 3(x + 1) + x?

Answer 1

Answer:

Given the equation: $2(x-3)+9=3(x+1)+x$

Distributive property of multiplication states that when a number is multiplied by the sum of the two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately i.e,

$a \cdot (b+c) = a\cdot b+a\cdot c$

Now, using distributive property to LHS and RHS, we get

$2x-6+9=3x+3+x$

Combine like terms on RHS;

$2x-6+9 = 4x+3$

or

$2x+3 = 4x+3$

Subtract 3 from both sides of an equation;

2x+3-3 =4x+3-3

Simplify:

2x = 4x

or

$4x-2x =0$

2x = 0

⇒ x =0

Therefore, the value of x in the given equation

$2(x-3)+9=3(x+1)+x$ is 0.

Answer 2

2(x – 3) + 9 = 3(x + 1) + x
2x - 6 + 9 = 3x + 3 + x
2x + 3 = 4x + 3
-2x        -2x

2x + 3 = 3
      - 3    -3

2x = 0
x = 0

Answer: The value of x is 0