Question

Help! You can look at the picture please

Answer 1

Answer:

$\frac{3x}{3 - 2x}$

Step-by-step explanation:

Here,

f(x) = y

$y = \frac{3x}{2x + 3}$

or , swapping x with y

$x = \frac{3y}{2y + 3}$

now to solve for y we get

$y = \frac{3x}{3 - 2x}$

now we put f inverse x instead of y

${f}^{ - 1} (x) = \frac{3x}{3 - 2x}$

I am done.

Answer 2

I think it’s D,but I’m not sure