Help!!!!!!!!!!!!!!!!!!!
1 answer:
You might be interested in
Answer:
The probability that the message will be wrong when decoded is 0.05792
Step-by-step explanation:
Consider the provided information.
To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.
We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.
The digit transmitted is incorrectly received with probability p = 0.2
The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8
We want the probability that the message will be wrong when decoded.
This can be written as:
Hence, the probability that the message will be wrong when decoded is 0.05792
They did not include the constraint for y ≤x+3 on the graph.
See attached picture with added constraint.
Using the 4 points that are given as the solution on the graph, replace t he x and Y in the original equation to solve and see which is the greater value.
Point (0,3) P = -0 +3(3) = 0+9 = 9
Point (1,4) P = -1 + 3(4) = -1 +12 = 11
Point (0,0) P = -0 + 3(0) = 0 + 0 = 0
Point (3,0) P = -3 + 3(0) = -3 + 0 = -3
The correct solution to maximize P is (1,4)
