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sashaice [31]
3 years ago
11

Write the formula of the function y whose graph is shown. A. Y equals 1 divided by x minus 4. B. Y equals 4 divided by the quant

ity x minus 4 end of quantity. C. Y equals 4 divided by the quantity x plus 4 end of quantity. D. Y equals 4 divided by x.

Mathematics
1 answer:
aliina [53]3 years ago
6 0

Answer:

Option D. Y equals 4 divided by x.

Step-by-step explanation:

The picture of the question in the attached figure

we know that

Looking a t the graph

For x=1, y=4

For x=4, y=1

For x=-1, y=-4

For x=-4, y=-1

therefore

The equation that satisfy  these values is

y=\frac{4}{x}

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A recipe for a loaf of bread requires 2/3 cup of flour. How many cups of flour would it take to make 15 loaves of bread?
Mars2501 [29]

Answer:

10

Step-by-step explanation:

1 loaf if bread= 2/3 cup

15 loaves of bread= 2/3 × 15

= 10

5 0
2 years ago
WILL GIVE A BRAINLEST!!!!!!
Andrej [43]
We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
 </span>- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2) 
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14
 
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or 
<span>all real numbers except c=-2 and c=2</span>


5 0
3 years ago
Read 2 more answers
What is 3.75 multiplied 2.6
Ivanshal [37]

Answer:

The answer to that is 9.75

Step-by-step explanation:

Hope this helps! Good luck

8 0
3 years ago
Read 2 more answers
If 6 sandwich rolls cost $1.44, how much will 26 rolls cost?
tresset_1 [31]

$6.24. This is because 1.44 / 6 = 0.24, and 0.24 x 26 = 6.24.

4 0
4 years ago
Read 2 more answers
Determine which of the indicated column vectors are eigenvectors of the given matrix
gladu [14]
]Eigenvectors are found by the equation (A-\lambda I) \vec{v} = 0$ implying that \det(A-\lambda I) = 0. We then can write:

A-\lambda I = \left [ \begin{array}{cc} 4-\lambda & 2 \\ 5 & 1-\lambda \end{array}\right ] 

And:

\det(A-\lambda I) = (4-\lambda)(1-\lambda) - 10 = 0 

Gives us the characteristic polynomial:

\lambda^2 - 5 \lambda -6 = 0 \implies \lambda_1 = -1, \lambda_2 = 6

So, solving for each eigenvector subspace:

\left [ \begin{array}{cc} 4 & 2 \\ 5 & 1 \end{array} \right ] \left [ \begin{array}{c} x \\ y \end{array} \right ] = \left [ \begin{array}{c} -x \\ -y \end{array} \right ]

Gives us the system of equations:

4x + 2y = -x \newline 5x + y = - y 

Producing the subspace along the line y = -\frac{5}{2} x

We can see then that 3 is the answer. 



7 0
3 years ago
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