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2 years ago

10

Margo soccer coach brings a large bag of watermelon to practice.the mass of the bag with all the watermelon in it is 12 kg. How

you could use estimation to figure out about how many watermelon are in the bag?

1 answer:

nirvana33 [79]2 years ago

4 0

6 watermelons, because each watermelon is 2 kg

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Mr. Tragrr has $500.00 to spend at a bicycle store. All the prices listed down below include tax.

fgiga [73]

To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.

Spent so far:

... 273.98 + 3×7.23 +42.36 = 338.03

Remaining available funds:

... 500.00 -338.03 = 161.97

The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.

Mr. Traeger can buy two (2) cycling outfits with the remaining money.

_____

The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.

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2 years ago

Read 2 more answers

PLEASE HELP V IMPORTANT<br> the answers I input were just so I could see other questions.

marishachu [46]

Step-by-step explanation:

(T-S)(2000), when T(x) and S(x) are functions, is equivalent to T(2000)-S(2000), which is 17-7=10

We know that T(x) is equal to everything else, and everything else is S(x)+G(x), so T(x)-S(x) = G(x), or dollars spent on general science

6 0

2 years ago

0.15(y-0.2)=2-0.5(1-y)<br><br> The answer is -153/35 I just need to know how to get that

butalik [34]

Answer:

$y=-\dfrac{153}{35}$ .

Step-by-step explanation:

The given equation is

$0.15(y-0.2)=2-0.5(1-y)$

Using distributive property, we get

$0.15(y)+0.15(-0.2)=2-0.5(1)-0.5(-y)$

$0.15y-0.03=2-0.5+0.5y$

$0.15y-0.03=1.5+0.5y$

Isolate variable terms.

$0.15y-0.5y=1.5+0.03$

$-0.35y=1.53$

Divide both sides by -0.35.

$y=\dfrac{1.53}{-0.35}$

$y=-\dfrac{1.53}{0.35}\times \dfrac{100}{100}$

$y=-\dfrac{153}{35}$

Therefore, $y=-\dfrac{153}{35}$ .

6 0

3 years ago

Help me please and thanks

lesya692 [45]

Answer:

3/-4 or -0.75 is the answer

Step-by-step explanation:

hope this is the right answer if it isnt sorryy

4 0

3 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

5 0

3 years ago