The graph that shows the solutions for the inequality, y > -1/3x + 1 is: C. Graph A.
<h3>How to Find the Graph of a Linear Inequality?</h3>
The inequality sign, ">" means that the graph of the inequality has a dashed line where the shaded part is above the boundary line and the boundary line is dashed or dotted. If "≥" is used, the boundary line would not be dashed or dotted and the shaded area would be above it.
On the other hand, "<" is used when the shaded area is below the boundary line and the boundary line is a dashed line. If "≤" was used, the boundary line won't be dashed or dotted, while the shaded area would be below the boundary line that is not dotted.
Given y > -1/3x + 1, the slope (m) = change in y / change in x is -1/3.
Graph A has a slope of -1/3 and the shaded part is above the boundary line.
Therefore, the graph that shows the solutions for y > -1/3x + 1 is: C. Graph A.
Learn more about inequality graph on:
brainly.com/question/24372553
#SPJ1
Answer:
-15626
you just multiply -5 by itself 6 times
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
If you are just looking for the derivative, then all you need to use the power rule for this. Technically the x in (x-9) has a power to the 1, so really x^1-9. To use power rule, you bring down the exponent, in this case, 1, and then minus 1 from what the exponent was.
1x^(1-1) = 1x^0. The derivative of any constant is 0, so don't even worry about the -9. We know that anything raised to the zero is just 1, so in this case your answer is 1.
Hope this helps :)
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
Answer:
2^6
Step-by-step explanation:
2*2*2*2*2*2
There are six 2's multiplied together so the base is 2 and the exponent is 6
2^6