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kirill115 [55]
3 years ago
5

Which triangles must be congruent?

Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0

Answer:

Δ ABC ≅ Δ FDE ≅ Δ GIH

Step-by-step explanation:

Between Δ ABC and Δ FDE, given that  

(i) AB = DF  

(ii) BC = HI and DE = HI, hence, BC = DE

(iii) ∠ B = ∠ D

Hence, by Side-Angle -Side i.e. SAS criteria Δ ABC ≅ Δ FDE

Again, between Δ ABC and Δ GIH, given that  

(i) AB = GI

(ii) BC = HI and  

(iii) ∠ B = ∠ I.

Hence, by Side-Angle-Side i.e. SAS criteria Δ ABC ≅ Δ GIH.

Therefore, Δ ABC ≅ Δ FDE ≅ Δ GIH (Answer)

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5x+7y=31 , 3x-5y=21??​
nikklg [1K]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
How many ways can 100 be written as the sum of distinct integers from the set {1, 2,..., 15}?
konstantin123 [22]

Answer:

48 ways

Step-by-step explanation:

Let me take a guess

S₁_₁₅ = (1+15)*7 + 8 = 120

There are 48 combinations of distinct digits from 1 to 15 to make 20

120-20=100

So every 20 has a corresponding 100

I wish I got it right, otherwise report it.

4 0
2 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
I WILL GIVE YOU BRAINLIEST NEED HELP PLEASEE :DD
Shtirlitz [24]

The coordinates of the pre-image of point F' is (-2, 4)

<h3>How to determine the coordinates of the pre-image of point F'?</h3>

On the given graph, the location of point F' is given as:

F' = (4, -2)

The rule of reflection is given as

Reflection across line y = x

Mathematically, this is represented as

(x, y) = (y, x)

So, we have

F = (-2, 4)

Hence, the coordinates of the pre-image of point F' is (-2, 4)

Read more about transformation at:

brainly.com/question/4289712

#SPJ1

8 0
2 years ago
Need help before 5:30pm i also have to show my work.
SpyIntel [72]

I can help!! But could you tell me what the equations are?

6 0
3 years ago
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