Ask question

Ask question

All categories

3 years ago

9

PLS HELP IM DUMB lol

1 answer:

Irina18 [472]3 years ago

4 0

No you are not divide it 2400÷3

You might be interested in

A researcher wishes to see if the average weights of newborn male infants are higher than the

faltersainse [42]

Answer:

The p-value is $p-value = 0.62578$

Step-by-step explanation:

From the question we are told that

The sample size of male infant is $n_1 = 12$

The sample size of female infant is $n_2= 9$

The sample mean of male infant is $\= x_1 = 7.70 \ lb$

The sample mean of female infant is $\= x_2 = 7.80 \ lb$

The population standard deviation is $\sigma = 0.5$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_ 1 = \mu_2$

The alternative hypothesis is $H_1 : \mu_1 > \mu_2$

The test statistics is mathematically represented as

$t =\frac{\= x_1 - \= x_2 }{\sqrt{\frac{\sigma }{n_1} } + \frac{\sigma }{n_2} } }$

=> $t = \frac{7.70 -7.80}{\sqrt{\frac{0.5 }{12} } + \frac{0.5 }{9} } }$

=> $t = -0.3207$

From the z-table the p-value is obtained, the value is

$p-value = P(Z > -0.3207) = 0.62578$

$p-value = 0.62578$

5 0

3 years ago

After a company celebrated its ten year anniversary, the president of the company wanted to know how long employees have been wi

finlep [7]

Step-by-step explanation:

The measures of variability is blank, the number that best summarizes the data is blank, and the number that best describes how the data varies is blank

Please send the box plot, I can solve it then but there is not enough info right here. Sorry!

7 0

3 years ago

Eric Bella Joan or Maya PLEASE HELP

TEA [102]

Joan did 21 is not a prime number good luck!!!

3 0

3 years ago

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

aalyn [17]

D as you distribute the 11 to multiply it by 23 and get -11x

4 0

3 years ago

Read 2 more answers