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KonstantinChe [14]
3 years ago
12

What activities belong at the top of the physical activity pyramid

Physics
1 answer:
amm18123 years ago
8 0

Answer: Cut down on watching tv, sitting down for more than 30 minutes at a time, and playing video games.

Explanation:

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The Henry's law constant for CO2 is 3.6 ✕ 10−2 M/atm at 25°C. What pressure (in atm) of carbon dioxide is needed to maintain a C
xeze [42]

To solve this problem we will use Henry's law. This law states that at a constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid. Mathematically it is formulated as follows:

C = K_H*P

Where,

K_H = Henry's constant for C02 at 25°C is equal to 3.6*10^{-2}M/atm

C = Gas concentration is 0.19M

Replacing we have,

0.19 M = (3.6*10^-2 M/atm)*P

P = 5.277 atm

Therefore the pressure of carbon dioxide is 5.277 atm

6 0
3 years ago
A crate which has a mass of m1 = 125kg is sitting on an icy surface. A rope is attached to the crate and held at angle theta 28.
devlian [24]

Answer:

μ = 0.109

Explanation:

Draw a free body diagram of the crate.  There are four forces:

Weight force mg pulling down.

Normal force N pushing up.

Applied force P pulling at θ above the horizontal.

Friction force Nμ pushing to the left.

Sum of the forces in the y direction:

∑F = ma

N + P sin θ − mg = 0

N = mg − P sin θ

Sum of the forces in the x direction:

∑F = ma

P cos θ − Nμ = ma

P cos θ − ma = Nμ

μ = (P cos θ − ma) / N

μ = (P cos θ − ma) / (mg − P sin θ)

Given:

P = 585 N

θ = 28.0°

m = 125 kg

a = 3.30 m/s²

μ = (585 cos 28.0° − 125 kg × 3.30 m/s²) / (125 kg × 9.8 m/s² − 585 sin 28.0°)

μ = 0.109

3 0
3 years ago
A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance. What is the maximum height reached by the
strojnjashka [21]

Answer:

the maximum height is 1.276 meters

4 0
2 years ago
The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?
xeze [42]
N2(g)<span> + 3H</span>2(g)<span> → 2NH</span><span>3(g) Is the answer. </span>
8 0
3 years ago
Read 2 more answers
Calculate the amount of heat liberated (in kj) from 411 g of mercury when it cools from 88.0°c to 12.0°c.
Katen [24]
You should note that the melting point of mercury is -38.83°C, while the boiling point is at 356.7°C. Then, that means that there is no latent heat involved here. We only compute for the sensible heat.

ΔH = mCpΔT
The Cp of mercury is 0.14 J/g·°C
Thus,
ΔH = (411 g)(0.14 J/g·°C)(88 - 12°C)
<em>ΔH = 4,373.04 J</em>
5 0
3 years ago
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