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TEA [102]
4 years ago
6

When a generator rotates a coil of wire in a magnetic field, which of the following is produced?

Physics
1 answer:
Sloan [31]4 years ago
4 0
The correct answer is an ''electric current''.
You might be interested in
a battery of 9v is connected in series with resistors of 0.2ohm , 0.3ohm, 0.5ohm, and 5 ohm respectively. how much current would
Nonamiya [84]

Answer:

1.5 A

Explanation:

Applying

V = IR'....................... Equation 1

make I the subject of the equation

I = V/R'.................. Equation 2

Where V = Voltage, I = current, R' = Total resistance.

From the question,

In a series connection,

R' = 0.2+0.3+0.5+5 = 6 ohm.

Given: V = 9V

Substitute into equation 2

I = 9/6

I = 1.5 A.

Note: Since all the resistors are connected in series, thesame current flows through them

Therefore the current flowing through the 5 ohm resistor = 1.5 A

5 0
3 years ago
A falling back in mid air has what
Umnica [9.8K]
Acceleration I think if I’m not mistaken
4 0
4 years ago
How long was a 50 W lightbulb left on for if 500,002 J were burned?
saveliy_v [14]

" 50 W " means " 50 Watts "  or  " 50 Joules per second ".

(500,002 J) / (50 J/sec)  =  <em>10,000.04 seconds</em>

(That's 2 hours 46 minutes 40.04 seconds.)

3 0
3 years ago
You're driving your new sports car at 85 mph over the top of a hill that has a radius of curvature of 525 m.
Bumek [7]

Explanation:

It is given that,

Speed of the sports car, v = 85 mph = 37.99 m/s

The radius of curvature, r = 525 m

Let W_N is the normal weight and W_A is the apparent weight of the person. Its apparent weight is given by :

W_A=mg-\dfrac{mv^2}{r}

So, \dfrac{W_A}{W_N}=\dfrac{mg-\dfrac{mv^2}{r}}{mg}

\dfrac{W_A}{W_N}=\dfrac{g-\dfrac{v^2}{r}}{g}

\dfrac{W_A}{W_N}=\dfrac{9.8-\dfrac{(37.99)^2}{525}}{9.8}

\dfrac{W_A}{W_N}=0.719

or

\dfrac{W_A}{W_N}=71.9\%

Hence, this is the required solution.

5 0
4 years ago
How many atoms of sodium do you have if you have one mole of sodium?
Yakvenalex [24]

Answer:

multiply the number of moles of Na by the conversion factor 6.02214179×1023 atoms Na/ 1 mol Na, with 6.02214179×1023 atoms being the number of atoms in one mole of Na (Avogadro's constant), which then allows the cancelation of moles, leaving the number of atoms of Na.

3 0
3 years ago
Read 2 more answers
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