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love history [14]
3 years ago
13

what happens to the current in a circuit if a 1.5 volt battery is removed and is placed by a 9 volt battery?

Physics
1 answer:
juin [17]3 years ago
8 0

Answer:

The current would increase.

Explanation:

The current would increase. 10. The relationship between resistance and current in a circuit is that the greater the resistance the less the current and the greater the current the less the resistance is.

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A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h
hram777 [196]

Answer:

v_{2}=3.5 m/s

Explanation:

Using the conservation of energy we have:

\frac{1}{2}mv^{2}=mgh

Let's solve it for v:

v=\sqrt{2gh}

So the speed at the lowest point is v=7 m/s

Now, using the conservation of momentum we have:

m_{1}v_{1}=m_{2}v_{2}

v_{2}=\frac{1*7}{2}

Therefore the speed of the block after the collision is v_{2}=3.5 m/s

I hope it helps you!

       

8 0
3 years ago
Alkaline earth metals have a low density<br><br><br> true<br> false
Marta_Voda [28]

true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

6 0
3 years ago
In your textbook reading Chapter 26, the author suggests that an electric vehicle (EV) fleet can be used as a kind of distribute
d1i1m1o1n [39]

Answer:

Answer for the question is given in the attachment.

Explanation:

Download pdf
8 0
3 years ago
A boy whirls a stone in a horizontal circle of radius 1.1 m and at height 2.1 m above ground level. The string breaks, and the s
DedPeter [7]

Answer:

212.8 m/s^{2}

Explanation:

Time taken by stone to cover horizontal distance

t=\sqrt{\frac {2h}{g}} where t is time, h is height of whirling the stone in horizontal circle, g is gravitational constant, Substituting h for 2.1 m and g for 9.81

t=\sqrt{\frac {2*2.1}{9.81}}= 0.654654 seconds

t=0.65 s

Velocity, v= distance/time

v=10/0.65= 15.27525 m/s

v=15.3 m/s

a=\frac {v^{2}}{r} where r is radius of circle, substituting r with 1.1m

a=\frac {15.3^{2}}{1.1}

a=212.8 m/s^{2}

Therefore, centripetal acceleration is 212.8 m/s^{2}

8 0
4 years ago
Why might a scientist repeat an experiment if she did not make a mistake in the first one?
iren2701 [21]

Answer:

B

Explanation:

4 0
3 years ago
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