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earnstyle [38]
3 years ago
6

What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1

Mathematics
1 answer:
Nuetrik [128]3 years ago
3 0

if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, \bf y=\stackrel{slope}{-2}x-1 has a slope of -2.


now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.


\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope =  m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5

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Can Someone plz help? Thx
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Step-by-step explanation:

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If you are given the diameter, just multiply it by pi, 3.14.

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