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bixtya [17]
3 years ago
8

What is the solution of x+4/2x-1<0

Mathematics
2 answers:
Sveta_85 [38]3 years ago
8 0

Answer:

x \in \bigg(-4,\displaystyle\frac{1}{2}\bigg)    

Step-by-step explanation:

We are given the following information in the question:

\displaystyle\frac{x + 4}{2x-1} < 0

Domain of given function:

2x - 1 \neq 0\\x \neq \displaystyle\frac{1}{2}

Th function is not defined on \frac{1}{2}

To solve the above inequality, we take the following steps:

\displaystyle\frac{x + 4}{2x-1} < 0\\\\x + 4 > 0 \text{ and } 2x-1 < 0\\x > -4\\2x - 1

In interval notation it can be written as:

x \in \bigg(-4,\displaystyle\frac{1}{2}\bigg)

Vikentia [17]3 years ago
3 0

Answer:

\large\boxed{ -4

Step-by-step explanation:

Domain:\ 2x-1\neq0\to x\neq\dfrac{1}{2}

\dfrac{x+4}{2x-1}

(x+4)(2x-1)=(x)(2x)+....=2x^2+...\to 2>0\\\\\text{therefore the parabola is op}\text{en up}

\text{Look at the picture.}

\dfrac{x+4}{2x-1}

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