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2 years ago

A donut shop made 12 dozen donuts to give to a school’s math club.

Mathematics

1 answer:

stepan [7]2 years ago

4 0

Answer:

d=doughnuts

x=students in math club

1 dozen = 12d

/ = divided by

. = multiply

(12.12)/x=

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A father is 60 yrs old son is half his age .How old was the boy when his father was four times his age

inna [77]

Let f be the fathers age and let s be the sons age

f = 60 s = 30
when f = 45
s = 15 which is only a third if his fathers age

when f = 40
s = 10 which is a quarter of his fathers age

therefore when his father was 4 times his age, the son was 10

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2 years ago

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Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

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Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

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Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

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where

b is the length side of the square

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$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

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$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

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$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

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$A=(49\pi -33)\ in^2$

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