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3 years ago

A donut shop made 12 dozen donuts to give to a school’s math club.

Mathematics

1 answer:

stepan [7]3 years ago

4 0

Answer:

d=doughnuts

x=students in math club

1 dozen = 12d

/ = divided by

. = multiply

(12.12)/x=

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Nat2105 [25]

Answer:

Step-by-step explanation:

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3 years ago

How do i solve 2 × =66

Aleks04 [339]

Answer:

You just have to divide the equation by "x"'s coefficient (2).

2x/2=x

66/2=33

x=33

Step-by-step explanation:

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3 years ago

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Artist 52 [7]

1. Add all of the numbers together
2. Divide the answer by how many different numbers there are (so 10)
The mean to the nearest tenth is 356.8

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3 years ago

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sergiy2304 [10]

Question 9

Given the segment XY with the endpoints X and Y

Given that the ray NM is the segment bisector XY

NM divides the segment XY into two equal parts

XM = MY

given

XM = 3x+1

MY = 8x-24

so substituting XM = 3x+1 and MY = 8x-24 in the equation

XM = MY

3x+1 = 8x-24

8x-3x = 1+24

5x = 25

divide both sides by 5

5x/5 = 25/5

x = 5

so the value of x = 5

As the length of the segment XY is:

Length of segment XY = XM + MY

= 3x+1 + 8x-24

= 11x - 23

substituting x = 5

= 11(5) - 23

= 55 - 23

= 32

Therefore,

The length of the segment = 32 units

Question 10)

Given the segment XY with the endpoints X and Y

Given that the line n is the segment bisector XY

The line divides the segment XY into two equal parts at M

XM = MY

given

XM = 5x+8

MY = 9x+12

so substituting XM = 5x+8 and MY = 9x+12 in the equation

XM = MY

5x+8 = 9x+12

9x-5x = 8-12

4x = -4

divide both sides by 4

4x/4 = -4/4

x = -1

so the value of x = -1

As the length of the segment XY is:

Length of segment XY = XM + MY

= 5x+8 + 9x+12

= 14x + 20

substituting x = 1

= 14(-1) + 20

= -14+20

= 6

Therefore,

The length of the segment XY = 6 units

8 0

3 years ago

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

6 0

3 years ago