The object must move with the speed of $\frac{\sqrt{3} }2}$ times to approximately seeing that it is contracted to exactly half of its actual length.

<h3>How is this calculated?</h3>

The length contraction experimented by the object as it approaches lightspeed, in meters per second, is described by Lorentz contraction formula:

$\frac{L}{L'} = \sqrt{(1) - (\frac{v}{c})^{2}$

Here, v is the current speed m/s

c is the speed of light in m/s

L' is the length of the object at rest in m

L is the length of the object at the current speed in m

Now we know that

$\frac{L}{L'}= \frac{1}{2}$ and $\frac{v}{c} = r$ then,

$\frac{1}{2} = \sqrt{1 - r^{2} }\\\frac{1}{4} = 1 - r^{2}\\r^{2} = \frac{3}{4}$

Hence, r = $\frac{\sqrt{3} }{2}$

Therefore, the answer is the object must travel at a speed of $\frac{\sqrt{3} }{2}$ times the lightspeed to be contracted to one-half its proper length.

To know more about the Lorentz contraction formula, visit:

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