Answer:
The 95% confidence interval = (98.225, 98.655)
Step-by-step explanation:
The formula for Confidence Interval =
Mean ± z × standard deviation/√n
Where Mean = 98.44°F
Standard deviation = 0.30°F
n = number of samples is 10
Because our number if samples is small, we use the t score confidence interval formula
Mean ± t × standard deviation/√n
Degrees of Freedom = n - 1
= 10 - 1 = 9
We find the t score of 95% confidence interval and degrees of freedom 9
= 2.262
Hence,
Confidence interval = 98.44 ± 2.262 × 0.30/√10
= 98.44 ± 0.214592162
Confidence Interval
98.44 - 0.214592162
= 98.225407838
≈ 98.225
98.44 + 0.214592162
= 98.654592162
≈ 98.655
The 95% confidence interval = (98.225, 98.655)
value of y which satisfies equation
is
.
<u>Step-by-step explanation:</u>
We have , 3y+8=7y+11 . We need to find which value of y satisfies this equation 3y+8=7y+11 :

⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore, value of y which satisfies equation
is
.
A. 1690.
You can get this answer by doing 13 to the power of 2 and then multiplying that answer by 10.
Answer:2/75
Step-by-step explanation:
2/5 1/15
2x1=2 15x5=75