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3 years ago

Find the distance between the points (3, -5) and (-6, -5).

Mathematics

1 answer:

Sophie [7]3 years ago

8 0

ANSWER

EXPLANATION

We want to find the distance between the points (3, -5) and (-6, -5).

The given points have the same y-coordinates .

This means it is a horizontal line.

We use the absolute value method to find the distance between the two points.

We find the absolute value of the distance between the x-values.

The distance between the two points is

|3--6|=|3+6|=|9|=9

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DETERMINE THE VALUE OF X BASED ON THE IMAGE DOWN BELOW:

Andre45 [30]

The answer is 80! If you ever see any angle like that where it’s just two lines (I don’t know how to explain it/forgot what it’s called) it will be the same as the other angle.

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2 years ago

Your class sells a box of oranges to raise $500 for a field trip.You earn $6.25 for each box of oranges sold.Write and solve an

emmainna [20.7K]

To do this, find the slope, y-intercept, and your goal.

Your goal is 500.
Your slope is 6.25 per orange.
Your y-intercept is 0 (you don't start out with anything.)

So, the inequality is $500 \leq 6.25x$ .

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3 years ago

Read 2 more answers

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago

5.6 as an improper fraction simplified?

Phoenix [80]

As a fraction, it would be 5 6/10. Then you multiply the denominator by the whole number 5x10 and add the numerator. So,
10X5+6=56
56/10
divide by 2
28/5 is the simplified version

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2 years ago

Gabbys age is two times mikhails age.the sum of their ages is 75. What is mikhails age

Tatiana [17]

Answer:

Mikhail's age is 25 years old

Step-by-step explanation:

Let's make an equation: Say Mikhail is x, so Gabby would be 2*x=2x

If the sum of their ages equals 75, then x+2x=75, and x=2x=3x, so 3x=75.

75/3=25

6 0

3 years ago